Answer:
= 2x
Step-by-step explanation:
Answer:
0.3165
Step-by-step explanation:
This is a binomial distribution problem
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of adults sampled = 9
x = Number of successes required = number of selected adults that say they were too young to get tattoos = 0
p = probability of success = probability of an adult that regrets getting a tattoo saying they were too young to get the tattoo = 12% = 0.12
q = probability of failure = 1 - p = 1 - 0.12 = 0.88
P(X=0) = ⁹C₀ (0.12)⁰ (0.88)⁹⁻⁰
P(X=0) = 0.31647838183 = 0.3165
Hope this Helps!!!
<h3>
Answer: 25</h3>
=================================================
Explanation:
Check out the image below. I've posted the synthetic division table. The value at the very end of the bottom row is the remainder. By the remainder theorem, this is exactly the value of g(-5).
Recall the remainder theorem says: If you divide p(x) by (x-k), then the remainder is p(k). In this case, k = -5 is our test root which is the value placed in the box on the left.
As a way to check the answer, we can say
g(x) = 2x^2 + 6x + 5
g(-5) = 2(-5)^2 + 6(-5) + 5
g(-5) = 25
So the answer is confirmed.
Probabilities are used to determine the chances of events
The probability that Jill selects a wooden pencil and then a mechanical pencil is 8%
<h3>How to calculate the probability</h3>
Represent the events as follows:
- A represents mechanical pencil
- B represents wooden pencil
- C represents colored pencil
So, we have
P(A) = 20%
P(B) = 40%
P(C) = 30%
The probability that Jill selects a wooden pencil and then a mechanical pencil is then calculated as:
P(B n A) = P(B) * P(A)
This gives
P(B n A) = 40% * 20%
Evaluate the product
P(B n A) = 8%
Hence, the probability that Jill selects a wooden pencil and then a mechanical pencil is 8%
Read more about probabilities at:
brainly.com/question/9385303
We want to find one-half of the reciprocal of 7/sqrt(98). Let's write down an expression for this:
![\dfrac{1}{2} \times \dfrac{\sqrt{98}}{7}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5Cdfrac%7B%5Csqrt%7B98%7D%7D%7B7%7D)
We can rewrite 98 into ![2 \times 49](https://tex.z-dn.net/?f=2%20%5Ctimes%2049)
![\dfrac{1}{2} \times \dfrac{\sqrt{2 \times 49}}{7}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5Cdfrac%7B%5Csqrt%7B2%20%5Ctimes%2049%7D%7D%7B7%7D)
![=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times \sqrt{49}}{7}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5Cdfrac%7B%5Csqrt%7B2%7D%20%5Ctimes%20%5Csqrt%7B49%7D%7D%7B7%7D)
The square root of 49 is 7
![=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times 7}{7}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5Cdfrac%7B%5Csqrt%7B2%7D%20%5Ctimes%207%7D%7B7%7D)
![=\dfrac{1}{2} \times\sqrt{2}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%5Csqrt%7B2%7D)
![=\dfrac{\sqrt{2}}{2}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D)
This should be your answer. Let me know if you need any clarifications, thanks!