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3 years ago

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Omar sells potato salad in his sandwich shop. Omar used the equation y= 2.89x to determine the total cost for different amounts

of potato salad. What is the cost of the potato salad at Omar’s Sandwich Shop (Like ___ Math input per pound)

1 answer:

ludmilkaskok [199]3 years ago

8 0

Answer:

$2.98

Step-by-step explanation:

x is how many units of potato salad were sold and y represents the total earnings

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Daniel put 38 stickers in each album

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A school gymnasium is being remodeled. The basketball court will be similar to an NCAA basketball court, which has a length of 9

valkas [14]

Answer:

Perimeter of NCAA court=288 feet

Perimeter of new court=259.2 feet

Step-by-step explanation:

We are given that

Length of NCAA court, l=94 feet

Width of NCAA court, b=50 feet

Width of new court, b'=45 feet

We have to find the perimeter of an NCAA court and new court in the school.

Perimeter of NCAA court= $2(l+b)$

Perimeter of NCAA court= $2(94+50)$ feet

Perimeter of NCAA court=288 feet

When two rectangles are similar then the ration of their corresponding sides are equal.

Using the property

$\frac{Perimeter\;of\;NCAA\;court}{Perimeter\;of\;new\;court}=\frac{Width\;of\;NCAA\;court}{Width\;of\;new\;court}$

$\frac{288}{Perimeter\;of\;new\;court}=\frac{50}{45}$

Perimeter of new court= $\frac{288\times 45}{50}$ feet

Perimeter of new court=259.2 feet

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3 years ago

Add: (x2 + 5x + 2) + (x2 - 2x + 7).

Varvara68 [4.7K]

The answer is c. Hope this helps!

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3 years ago

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

$b_{1}$ be the shorter base

$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

or, $b_{1}+b_{1}+6 = \frac{(72)(2)}{6}$

or, $2b_{1}+6 = 24$

or, $2b_{1}=24-6$

or, $b_{1}= \frac{18}{2}$

or, $b_{1}=9$

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

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3 years ago

How can i solve this ?

ExtremeBDS [4]

Answer: X > 100

Step-by-step explanation:

X - 19 < 81

Once the less than sign is turned over

X > 81 +19

X > 100

Thus, the value of X must be greater than 100

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