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mojhsa [17]
2 years ago
14

Jacob spends 60 minutes in the gym every day doing freehand exercises and running on the treadmill. He runs on the treadmill for

30 minutes longer than he does freehand exercises.
Part A: Write a pair of linear equations to show the relationship between the number of minutes Jacob does freehand exercises (y) and the number of minutes he runs on the treadmill (x).


Part B: How much time does Jacob spend doing freehand exercises? Show your work.


Part C: Is it possible for Jacob to have spent 40 minutes running on the treadmill if he spends exactly 60 minutes total at the gym and runs on the treadmill for 30 minutes longer than he does freehand exercises? Explain your reasoning.
Mathematics
1 answer:
Flauer [41]2 years ago
3 0
Jacob spends 90 minutes on the treadmill
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The magnitude of the resultant vector shown is _____.
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Answer:

  2√3

Step-by-step explanation:

You recognize this as a 30°-60°-90° triangle, so you know the hypotenuse (R) is twice the length of the shortest side (√3).

The magnitude of R is 2√3.

_____

In case you haven't memorized the ratios for a 30°-60°-90° triangle, you can use trigonometry and the fact that ...

  Sin = Opposite/Hypotenuse

  sin(30°) = √3/R

  R = √3/sin(30°) = √3/(1/2) = 2√3

Of course, doing this on your calculator will give a numerical answer, which you may not want.

6 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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3 years ago
Erica measures the mass of a steel ball several different times. If Erica's results are highly precise, this must mean that A. m
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C is the answer you are looking for.
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4 years ago
-4(x+1)+5=17 solve for x
ahrayia [7]

-4(x + 1) + 5 = 17

Distribute -4 inside the parentheses.

(-4x - 4) + 5 = 17

Combine like terms (-4 + 5).

-4x + 1 = 17

Subtract 1 from both sides.

-4x = 16

Divide both sides by -4.

x = -4

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Break into 2 equatins to get x's:

2x-6<4 and 2x-6>-4

Solve for x in both:

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2x-6>-4
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Graph both inequalities on the same number line:

<---0-----1-----2-----3-----4-----5-----6--->
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