This question is based on least common multiple method.
As given in the question,
Aunts are taking pictures in group of = 5
Uncles are taking pictures in group of = 10
So we have been asked what is the minimum number of aunts Sana have.
As we have been given that the number of aunts and uncles is equal so to find the minimum number of aunts we will apply the least common multiple method.
So we get LCM of 5,10 as 10
Hence there are minimum 10 aunts.
Answer:
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Step-by-step explanation:
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Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)