Which value would make the inequality ⅓ R > 12 true? <br> a. 39<br> b. 36 <br>c. 7 <br>d. 4

Plzzz helpppppp nowwwww

snow_lady [41]

Answer:

x= 10

I hope i helped, best of luck!

4 0

2 years ago

Read 2 more answers

Which ordered pair represents the y-intercept of the graph of the equation y = -3x - 9?

Mnenie [13.5K]

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Equation
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y = -3x - 9

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Option 1
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If I substitute x = -9, I should get y = 0

When x = -9
y = -3 (-9) - 9
= 18 (I did not get 0, wrong)

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Option 2
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If I substitute x = -3, I should get y = 0
y = -3(-3) - 9
y = 9 - 9
y = 0 (Yes, I got 0, correct)

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Option 3
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If I substitute x = 0, I should get y = -3
y = -3 (0) - 9
y = 0 - 9
y = -9 (I did not get -3, wrong)

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Option 4
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If I substitute x = 0, I should get y = -9
y = -3 (0) - 9
y = 0 - 9
y = -9 (Yes, I got -9, correct)

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Answer: (-3, 0) and (0, 9) are ordered pairs of the equation (Answer B, D)
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7 0

3 years ago

The equation of a circle is given below. (x-0.5)^{2}+(y-3.5)^{2} = 16(x−0.5) 2 +(y−3.5) 2 =16left parenthesis, x, minus, 0, poin

Mashutka [201]

Answer:

<h2>The radius is 4 units long.</h2>

Step-by-step explanation:

The given equation is

$(x-0.5)^{2} +(y-3.5)^{2} =16$

This equation belongs to a circle, which center is at (0.5, 3.5) and its radius is 4.

You can deduct its elements, becase this equation of the circle is explicit, which means the constant term represents the square power of the radius. Solving that, we have

$r^{2} = 16\\r=\sqrt{16}\\ r=4$