Are there any verticals angles? If so name them.

A soft drink machine outputs a mean of 27 ounces per cup. The machine's output is normally distributed with a standard deviation

postnew [5]

Answer: P(22 ≤ x ≤ 29) = 0.703

Step-by-step explanation:

Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = output of the machine in ounces per cup.

µ = mean output

σ = standard deviation

From the information given,

µ = 27

σ = 3

The probability of filling a cup between 22 and 29 ounces is expressed as

P(22 ≤ x ≤ 29)

For x = 22,

z = (22 - 27)/3 = - 1.67

Looking at the normal distribution table, the probability corresponding to the z score is 0.047

For x = 29,

z = (29 - 27)/3 = 0.67

Looking at the normal distribution table, the probability corresponding to the z score is 0.75

Therefore,

P(22 ≤ x ≤ 29) = 0.75 - 0.047 = 0.703

6 0

3 years ago

Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n

Temka [501]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= $\frac{3}{8}$ of x

Total number of newspapers delivered in first hour= $\frac{3}{8}$ x

Number of newspapers left= x- $\frac{3x}{8}$

Number of newspapers left= $\frac{8x-3x}{8}$

Number of newspapers left= $\frac{5x}{8}$

Number of newspapers delivered in second hour=4/5 of $\frac{5x}{8}$

Number of newspapers delivered in second hour= $\frac{x}{2}$

Fraction of newspapers delivered in second hour is= $\frac{1}{2}$

Hence, the correct answer is $\frac{1}{2}$

8 0

3 years ago

If f(x) = 3x^2 – 2x + 4 and g(x) = 5x^2 + 6x – 8, find (f - g)(x).

meriva

Answer:

$-2x^2-8x+12$

Step-by-step explanation:

$f-g=(3x^2-2x+4)-(5x^2+6x-8)=3x^2-2x+4-5x^2-6x+8=\\ =-2x^2-8x+12$

5 0

3 years ago

Read 2 more answers

Please help me with those question please help with out number 1

alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

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2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

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3)

x = 0, y = 1

x = 1, y = $\frac{7}{5}$

x = 5, y = 3

x = 10, y = 5

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4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

$y=5x+5$

When x = 0, y = ?

$y=5(0)+5\\y=0+5\\y=5$

When x = 1, y = ?

$y=5(1)+5\\y=5+5\\y=10$

When x = 2, y = ?

$y=5(2)+5\\y=10+5\\y=15$

When x = 3, y = ?

$y=5(3)+5\\y=15+5\\y=20$

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2)

$y=5x-2$

When x = 0, y = ?

$y=5(0)-2\\y=0-2\\y=-2$

When x = 2, y = ?

$y=5(2)-2\\y=10-2\\y=8$

When x = 4, y = ?

$y=5(4)-2\\y=20-2\\y=18$

When x = 6, y = ?

$y=5(6)-2\\y=30-2\\y=28$

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3)

$y=\frac{2}{5}x +1$

When x = 0, y = ?

$y=\frac{2}{5}(0) +1$

$y=0 +1\\y=1$

When x = 1, y = ?

$y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1$

$y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5} \\y=\frac{7}{5}$

When x = 5, y = ?

$y=\frac{2}{5}(5) +1\\y=2+1\\y=3$

When x = 10, y = ?

$y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5$

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4)

$y=15x+2$

When x = 0, y = ?

$y=15(0)+2\\y=0+2\\y=2$

When x = 1, y = ?

$y=15(1)+2\\y=15+2\\y=17$

When x = 2, y = ?

$y=15(2)+2\\y=30+2\\y=32$

When x = 5, y = ?

$y=15(5)+2\\y=75+2\\y=77$

4 0

3 years ago

Read 2 more answers

Adding negative numbers

jekas [21]

Step-by-step explanation:

-5 × -5 = 25

-6 + 5 = 1

-3 + 5 = -8

6 0

3 years ago