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Sauron [17]
3 years ago
10

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Mathematics
1 answer:
yarga [219]3 years ago
7 0
-1.55,-1.5,-1.05,-1.0
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Helpppppppppppppppppppppppppppppppppp
iragen [17]

The answer you are looking for is 14.69.

3 0
3 years ago
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The two triangles are congruent as suggested by their appearance. Find the value of c . The diagrams are scale
jeyben [28]

If the triangles are congruent, then their corresponding parts are also congruent.


First check to make sure the orientation of the triangles is correct. This is so we can easily compare corresponding parts.

Angle d is 180-90-52 = 38 degrees (sum of interior angles of triangle is 180 degrees), and this is the same as the angle on the triangle on the left.


Therefore the side with a length of 3 units is congruent to side c, which means side c is 3 units.


4 0
4 years ago
1 + xThe function g is defined by g(x)=7+2xFind g(a+5).
vredina [299]

The function is given as:

g(x)=\frac{1+x}{7+2x}

We need to find the expression g(a + 5).

This means that we are going to plug in "a + 5" into "x" of the function. So, substituting, it gives us,

\begin{gathered} g(x)=\frac{1+x}{7+2x} \\ g(a+5)=\frac{1+(a+5)}{7+2(a+5)} \end{gathered}

Now, we need to simplify the expression. Steps are shown below:

\begin{gathered} g(a+5)=\frac{1+(a+5)}{7+2(a+5)} \\ =\frac{1+a+5}{7+2a+10} \\ =\frac{6+a}{17+2a} \end{gathered}Answer\frac{6+a}{17+2a}

5 0
1 year ago
Find the value of x.
dimaraw [331]

Answer:

x= 30°

Step-by-step explanation:

The shape is irregular, and it has 5 angles, and the formula for finding a n-sided polygon

is (n-2)180°. To get the total angle, (5-2)180°=3×180°=540°. X°+4x°+4x°+135°+135°=540° ; 9x°+270°=540° ; 9x°=540°-270° ; 9X°=270° therefore, X=270°÷9= 30°•

8 0
3 years ago
Guys please help me on this I’m so stuck
Sergio [31]

Answer:

It is the third option

Step-by-step explanation:

ln(xy)=ln(x)+ln(y)

ln(x/y)=ln(x)−ln(y)

ln(xy)=yln(x)

use these three rules, first separate the fraction out to log(\log (x^2-6)^4 - \log \sqrt[3]{x^2+8} , then take the exponent and root out to make 4\log (x^2-6)- \frac{1}{3} \log x^2+8

7 0
4 years ago
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