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Kipish [7]
3 years ago
15

Simply using order of operations 20 - (4*2) ÷ (5-3)

Mathematics
2 answers:
Talja [164]3 years ago
4 0

Answer:

16

Step-by-step explanation:

First, you have to follow the order of operations. (PEMDAS) So you would simplify the numbers inside of  the parenthesis, (4*2), and (5-3). The equation then becomes 20 - (8) / (2). Next, you do multiplication and division next, since  there is no exponent. 20 - 4. You then simplify the rest by subtracting. 20 - 4 = 16. There is your answer.

Keith_Richards [23]3 years ago
3 0
The answer is 6 because you have to first find the answer for (4*2) and (5-3)
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Evan and Ian are selling wrapping paper for a fundraiser. Evan sold twice as many rolls of wrapping paper as Ian. If Evan sold 1
swat32

Answer:

Ian sold 7 rolls of wrapping paper.

Step-by-step explanation:

Let E be the number of rolls of wrapping paper sold by Evan and I be the number of rolls of wrapping papers sold by Ian.

We have been given that Evan sold twice as many rolls of wrapping paper as Ian. We can represent this information in an equation as:

E=2I...(1)

We are also told that Evan sold 14 rolls.

We can represent this information in an equation as:

E=14...(2)

To find the number of rolls of wrapping paper sold by Ian we will equate our both equation as:

2I=14

Let us divide both sides of our equation by 2.

\frac{2I}{2}=\frac{14}{2}

I=7

Therefore, Ian sold 7 rolls of wrapping paper.

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3 years ago
Fiona has 6 garden boxes. She wants to plant 3 vegetable seeds and 3 flowers seeds in each garden box. How many seeds does Fiona
Mrrafil [7]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
What's the answer to 1&2 plzz
Alexeev081 [22]
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5 0
3 years ago
I need to do b and d
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3 years ago
Write the following quotient in the form a+bi.<br> -7i/2-7i
Helga [31]

Answer:

\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}

Step-by-step explanation:

\text{Use}\\\\i=\sqrt{-1}\to i^2=-1\\\\(a-b)(a+b)=a^2-b^2\to(a-bi)(a+bi)=a^2+b^2\\\\\text{distributive property}\ a(b+c)=ab+ac\\---------------------\\\\\dfrac{-7i}{2-7i}=\dfrac{-7i}{2-7i}\cdot\dfrac{2+7i}{2+7i}=\dfrac{-7i(2+7i)}{2^2+7^2}=\dfrac{(-7i)(2)+(-7i)(7i)}{4+49}\\\\=\dfrac{-14i-49i^2}{53}=\dfrac{-14i-49(-1)}{53}=\dfrac{-14i+49}{53}\\\\=\dfrac{49}{53}-\dfrac{14}{53}i

8 0
3 years ago
Read 2 more answers
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