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Alexus [3.1K]
3 years ago
11

At a local fitness center, gym members pay $3 per workout with an annual membership fee of $140. Non-members pay $10 per workout

. If you plan on working out an average of twice a month for the next year, is a membership worth the investment? Show your thinking
need help asap pls ill brain list and 5 star
Mathematics
1 answer:
andriy [413]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

going to the gym for 12 months two times each time u go its 10 dollars so u would spend $20 each month whichis is $288 for 12 moths thats the total so make the investment and save money

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A snowstorm began on Monday evening. It snowed steadily until 6:00 am on Tuesday morning when the snow was 12 inches deep. Kevin
poizon [28]

Answer:

what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

Step-by-step explanation:

In this question, we are asked to calculate if the prediction made by an equation modeled is correct.

Firstly let’s look at the equation in question;

y = 3t - 6

where y is the snow depth and t is the number of hours after midnight.

now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.

let’s plug the value of t as 7 into the equation

y = 3(7) - 6

y = 21-6

y = 15 inches

according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

3 0
3 years ago
How deep the water 50 ft from the shore ?
PIT_PIT [208]
400 ft. Hope it helps. Pls Give brainliest answer!
8 0
3 years ago
On a scale drawing of a museum, two water fountains are 10 inches apart. The actual distance between them is 400 feet. On the sa
AysviL [449]
The answer is 125 feet. I hope I helped.
6 0
3 years ago
Read 2 more answers
What is the difference of
ki77a [65]

Answer:

Step-by-step explanation:

the difference is 56 because if you add and divide them by 3 and -2 you will get 56

6 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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