X^2+ 4 x + 4 pls tell this insteps
2 answers:
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Answer:
f(-x)= -f(x) so, the given function is Odd
Step-by-step explanation:
We need to determine if the function is Even, Odd, or Neither.
Determining if a function f(x) is even or not we put x=-x and check
If f(-x)=f(x) the function is even
if f(-x)= -f(x) the function is odd
So, Putting x =-x and determining if the given function is Even, Odd, or Neither.
As f(-x)= -f(x) so, the given function is Odd
Answer:
a)g: 3x + 4y = 10 b) a:x+y = 5 c) c: 3x + 4y = 10
h: 6x + 8y = 5 b:2x + 3y = 8 d: 6x + 8y = 5
Step-by-step explanation:
a) Has no solution
g: 3x + 4y = 10
h: 6x + 8y = 5
Above Equations gives you parallel lines refer attachment
b) has exactly one solution
a:x+y = 5
b:2x + 3y = 8
Above Equations gives you intersecting lines refer attachment
c) has infinitely many solutions
c: 3x + 4y = 10
d: 6x + 8y = 5
Above Equations gives you collinear lines refer attachment
i) if we add x + 2y = 1 to equation x + y = 5 to make an inconsistent system.
ii) if we add x + 2y = 3 to equation x + y = 5 to create infinitely system.
iii) if we add x + 4y = 1 to equation x + y = 5 to create infinitely system.
iv) if we add to x + y =5 equation x + y = 5 to change the unique solution you had to a different unique solution
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²