A is (-1,0) B is (0,-3) C is line of symmetry D is (3,0) E is (2,-3) F is (1, -4)
Y = (x - 1)² + 2
y = (x² - x - x + 1) + 2
y = (x² - 2x + 1) + 2
y = x² - 2x + (1 + 2)
y = x² - 2x + 3
x² - 2x + 3 = 0
x = <u>-(-2) +/- √((-2)² 4(1)(3))</u>
2(1)
x = <u>2 +/- √(4 + 12)</u>
2
x = <u>2 +/- √(16)
</u> 2<u>
</u>x = <u>2 +/- 4
</u> 2<u>
</u>x = 1 <u>+</u> 2
x = 1 + 2 x = 1 - 2
x = 3 x = -1
y = x² - 2x + 3
y = (3)² - 2(3) + 3
y = 9 - 6 + 3
y = 3 + 3
y = 6
(x, y) = (3, 6)
or
y = x² - 2x + 3
y = (-2)² - 2(-1) + 3
y = 4 + 2 + 3
y = 6 + 3
y = 9
(x, y) = (-1, 9)
Answer:
B
Step-by-step explanation:
X= 5
multipules of 5
thinking of the factors of 5
