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Dmitry_Shevchenko [17]
3 years ago
12

PLEASE HELP ITS ALMOST DUE

Mathematics
1 answer:
taurus [48]3 years ago
6 0

Answer:

we have"

\frac{q}{36}=\frac{16-q}{28}\\\\28q=36(16-q)\\\\28q=576-36q\\\\64q=576\\\\=>q=9

Step-by-step explanation:

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Given that (5,-8) is on the graph of f(x), find
My name is Ann [436]

Answer:

The corresponding point for the function  f(x + 2) is (3 , -8)

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) translated horizontally to the right  by h units,

 then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  by h units,

 then the new function g(x) = f(x + h)

* Lets solve the problem

- There is a graph of f(x)

- Point (5 , -8) lies on the graph of f(x)

- The graph of f(x) change to f(x + 2)

∵ f(x) ⇒ f(x + 2)

∵ If the function f(x) translated horizontally to the left  by h units,

  then the new function g(x) = f(x + h)

∴ f(x) translated horizontally 2 units to the left

∴ Any point on the graph its x-coordinate translated 2 units

  to the left

∴ The x-coordinate of any point on the graph is subtracted by 2

∵ Point (5 , -8) lies on the graph

∴ Its corresponding point is (5 - 2 , -8) = (3 , -8)

* The corresponding point for the function  f(x + 2) is (3 , -8)

7 0
3 years ago
Does anyone know the answer?
motikmotik

Answer:

We conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.          

Step-by-step explanation:

From the given right-angled triangle,

  • Base = p+1
  • Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

                                            =\frac{1}{2}\left(p+1\right)\left(2p-6\right)

Factor 2p-6: 2(p-3)

                                             =\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}  

Divide the number: 2/2 = 1

                                              =\left(p+1\right)\left(p-3\right)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

                                               =pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)

                                               =pp-3p+1\cdot \:p-1\cdot \:3

                                                =p^2-2p-3

Therefore, we conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.                                        

3 0
3 years ago
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