Answer:

Step-by-step explanation:
Given
See attachment for soccer field
Required
The possible dimension of the field
From the attachment, we have:



So, we have:

This gives:

Express 36 as 6^2

Express as difference of two squares

Hence, the dimension is: 
Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.
Perimeter=40ft
The perimeter of a rectangle is:
P=2l+2w
Since we know the length is 5 and the perimeter is 40, we can solve for the width.
P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w
The width of the fence is 15feet.
A is the correct answer !
Answer:
The x-intercept is 2.
Step-by-step explanation:
![2 \sqrt[3]{x - 10} + 4 = 0](https://tex.z-dn.net/?f=2%20%5Csqrt%5B3%5D%7Bx%20-%2010%7D%20%20%2B%204%20%3D%200)
![2 \sqrt[3]{x - 10} = - 4](https://tex.z-dn.net/?f=2%20%5Csqrt%5B3%5D%7Bx%20-%2010%7D%20%20%3D%20%20-%204)
![\sqrt[3]{x - 10 } = - 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20-%2010%20%7D%20%20%3D%20%20-%202)


Answer:
I'm sorry I can help you maybe a little bit if that's okay. Btw what grade are you in?
Step-by-step explanation: