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likoan [24]
3 years ago
15

Prove that (1/sinx- cosx/sinx)^2 =1-cosx/1+sinx​

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Step-by-step explanation:

from lhs

(1/sinx-cosx/sinx)^2

1-cosx/sinx)^2

1-sinx^2-cosx

1-cosx/1+sinx

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Step-by-step explanation:

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3 years ago
0.6(4-2x)=20.5-(3x+10)
solong [7]

The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5

<u>Solution:</u>

Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )

We have to solve the above given equation for x.

Now, take the equation  

\rightarrow 0.6(4-2 x)=20.5-(3 x+10)

We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction

On solving the brackets, we get

\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10

Now multiplication is given preference

\rightarrow 2.4-1.2 x=10.5-3 x

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Now subtraction is done

\rightarrow 1.8 \mathrm{x}=8.1

Now division is performed

\rightarrow x=\frac{8.1}{1.8}=4.5

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5 0
3 years ago
What is 13 - 4 x = 1 - x?
Zinaida [17]

Answer:

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Step-by-step explanation

7 0
3 years ago
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Answer:

The answer is 36°.

Hope it helps.

Step-by-step explanation:

• • •

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