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2 years ago

Write each power as a product of the same factor. Then find the value. 7^2

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

3 0

Answer:

Step-by-step explanation:

7^2=49

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Brown tree snakes are an invasive species causing huge environmental and financial damage in Guam. Researchers captured brown tr

storchak [24]

Answer:

Null Hypothesis, $H_0$ : $\mu$ $\leq$ 120 grams

Alternate Hypothesis, $H_A$ : $\mu$ > 120 grams

Step-by-step explanation:

We are given that researchers captured brown tree snakes on Guam's Andersen Air Force Base, and a random sample of 250 of these snakes were weighed.

The researchers want to perform a hypothesis test to see if the mean weight of a brown tree snake in Guam is significantly greater than 120 grams.

Let $\mu$ = mean weight of a brown tree snake in Guam.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 120 grams

Alternate Hypothesis, $H_A$ : $\mu$ > 120 grams

Here, null hypothesis states that the mean weight of a brown tree snake in Guam is smaller than or equal to 120 grams.

On the other hand, alternate hypothesis states that the mean weight of a brown tree snake in Guam is significantly greater than 120 grams.

So, this would be the appropriate null and the alternative hypothesis to test this claim.

8 0

2 years ago

What is the slope for a line that passes through (2,5) and (6,7)?

Lady bird [3.3K]

Answer:

1/2

Step-by-step explanation:

slope = (y-y1)/(x-x1)

= (7-5)/(6-2)

=2/4 = 1/2

4 0

2 years ago

Read 2 more answers

Logify the problem 5x+2+3=25

77julia77 [94]

the answer is x=4.

5 0

2 years ago

Use the distributive property to remove the parentheses. (v-2)9

Sunny_sXe [5.5K]

Answer:

9v-18

Step-by-step explanation:

.........................................

5 0

2 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago