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4 years ago

Are Simple statements are often just called statements

Mathematics

1 answer:

Ksju [112]4 years ago

7 0

Yes they are because if I made a small statement like oh I like your shirt it's still called a statement.

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X2 + 1/2x +__ = 2 + __

Brut [27]

Complete the Square:

$\frac{b}{2a}$ Plug your numbers in this function

$\frac{\frac{1}{2} }{2}$ You get this

That equals $\frac{1}{4}$

3 0

4 years ago

Read 2 more answers

Please answer and explain

sashaice [31]

8=2*2*2=2^3
32=2*2*2*2*2=2^5
<span>[8^(2/3)] / [32^(2/5)] = [</span>(2^3)^(2/3)] / [(2^5)^(2/5)] =
= [2^(3*2/3)] / [2^(5*2/5)]= [2^2] / [2^2] = 4/4 = 1
Answer: 1

4 0

3 years ago

(8Q) Tell whether the function exhibits damped oscillation. If it does, identify the damping factor and tell whether the damping

dezoksy [38]

Answer:

Option c.

No damping

Step-by-step explanation:

We can easily solve this question by using a graphing calculator or any plotting tool.

The function is

f(x) = (√11)*cos(3.7x)

Which can be seen in the picture below

We can notice that f(x) is a cosine with maximum amplitude of (√11). Neither this factor nor the multiplication of x by 3.7 serve as a damping factor since they are constants.

f(x) does not present any dampening

5 0

4 years ago

Read 2 more answers

If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?

oksano4ka [1.4K]

$\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

Given $\boxed{ \ a(x) = 3x + 1 \ }$ and $\boxed{ \ b(x) = \sqrt{x - 4} \ }$ .

We will form (b o a)(x) and then determine the domain.

$\boxed{ \ (b \circ a)(x) = b(a(x)) \ }$

Replace each appearance of x in b(x) with $\boxed{ \ a(x) = 3x + 1 \ }$ .

$\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }$

Thus, $\boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }$

To be defined, the value under the radical sign must not be negative. Therefore, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ are processed as follows.

$\boxed{ \ 3x - 3 \geq 0 \ }$

Both sides added by 3.

$\boxed{ \ 3x \geq 3 \ }$

Both sides divided by 3.

$\boxed{ \ x\geq 1 \ }$

Thus, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ is $\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Learn more</h3>

If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
Solve for the value of the function composition brainly.com/question/2142762
Look for rotation rules in the transformation brainly.com/question/2992432

Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,

4 0

4 years ago

Read 2 more answers

Please explain in simple language how to complete the square.

dsp73

Answer:

Step 1 Divide all terms by a (the coefficient of x2).

Step 2 Move the number term (c/a) to the right side of the equation.

Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.

Step-by-step explanation:

hope i helped

3 0

3 years ago