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deff fn [24]
2 years ago
9

A medium-sized highway construction company CST has chosen to constrain its investment in computing resources to laptop and desk

top computers and the necessary networking hardware and software to access the Internet efficiently. All of CST's data is to be stored off-site through an Internet-enabled storage provider that is used by many different companies and organizations. The service model employed for the data storage capability of only CST is:
Computers and Technology
1 answer:
Valentin [98]2 years ago
5 0

Answer:

The service model employed for the data storage capability of only CST is:

SaaS (Software as a Service).

Explanation:

The three cloud computing categories are Infrastructure as a Service (IaaS), Software as a Service (SaaS), and Platform as a Service (PaaS).  The three cloud computing services provide different virtual computing resources.  In the case of CST, it utilizes only the data storage software of a provider, who provides the data storage infrastructure, including cloud-based servers, while CST uses its own "laptop and desktop computers and other networking hardware and software to access the Internet efficiently."

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Write a method named circleArea that accepts the radius of a circle as a parameter (as a real number) and returns the area of a
lions [1.4K]

Answer:

  public static double circleArea(double radius){

       double area = 3.142*Math.pow(radius,2);

       return area;

   }

Explanation:

Find the complete program in java that prompts the user to enter a value for radius, stores it in a variable, calls the method circleArea() and passes the value for the radius, then displays the area.

import java.util.Scanner;

public class CocaColaVendingTest {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Please enter the value for radius");

       double r = in.nextDouble();

       //Calling the method circleArea()

       double calcArea = circleArea(r);

       System.out.println("The Area is: "+calcArea);

   }

   public static double circleArea(double radius){

       double area = 3.142*Math.pow(radius,2);

       return area;

   }

}

6 0
2 years ago
Wyjaśnij w jaki sposób wykonuje się nitowanie zakładkowe i nakładkowe, oraz wyjaśnij na czym polega pasowanie mieszane.
Ksenya-84 [330]

Answer:

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Explanation:

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7 0
3 years ago
Where is the Outlook Search Folder located?
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6 0
3 years ago
Consider the following algorithms. Each algorithm operates on a list containing n elements, where n is a very large integer.
DochEvi [55]

We have that the appropriate statement will be

  • An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

From the question we are told

Consider the following <u>algorithms</u>. Each <u>algorithm</u> operates on a list containing n <em>elements</em>, where n is a very large <u>integer</u>.

I. An algorithm that accesses each <u>element</u> in the list twice.

II. An <em>algorithm </em>that accesses each <u>element </u>in the list n times.

III. An <u>algorithm</u> that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the <em>algorithms </em>run in <em>reasonable </em>time?

<h3>Algorithm  </h3>

Generally In order to get <em>admission </em>to every thing in the list twice, the algorithm has to traverse the listing twice,

which leads to 2*n entry to operations.

And if the every factor is accessed n times, the listing will be traversed n time, which leads to n^2 get right of entry to operations.

If n is a very giant <em>integer</em>, each 2*n and n^2 are plenty larger.

So, there will be <em>solely </em>ten entry to operations and this algorithm will have a sensible jogging time.

Therefore

An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

For more information on  algorithm  visit

brainly.com/question/950632

4 0
2 years ago
Create an array to hold the rainfall values. Create a 2nd parallel array (as a constant) to hold the abbreviated names of the mo
Zarrin [17]

Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

float lowRain, highRain, total, avg;

 

//array declaration

float rainfall[13];

char monthName[13][10] = {"", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

//get user input

for(int i=1; i<=12; i++)

{

printf("Enter the rainfall (in inches) for %s: ", monthName[i]);

scanf("%f", &rainfall[i]);

}

 

//display the monthly rainfall

printf("\nThe rainfall that was entered was:\n");

for(int i = 1; i<=6; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 1; i<=6; i++)

printf("%.1f ", rainfall[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%.1f ", rainfall[i]);

 

//variable initialization

low = 1;

high = 1;

lowRain = rainfall[1];

highRain = rainfall[1];

total = 0;

 

//calculate the lowest, highest and averaage rainfall

for(int i=1; i<=12; i++)

{

if(lowRain>rainfall[i])

{

lowRain = rainfall[i];

low = i;

}

if(highRain<rainfall[i])

{

highRain = rainfall[i];

high = i;

}

total = total + rainfall[i];

}

 

avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

printf("\nThe average monthly rainfall was %.1f inches.", avg);

printf("\nThe lowest monthly rainfall was %.1f inches in %s.", rainfall[low], monthName[low]);

printf("\nThe highest monthly rainfall was %.1f inches in %s.", rainfall[high], monthName[high]);

return 0;

}

4 0
3 years ago
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