Answer:
The answer is below
Explanation:
a) Seek time = 5 msec, transfer time = 4 msec, transfer rate = 8 MB/sec = 8000 KB/sec, average file size = 8 KB
Transfer time = 8 KB ÷ 8000 KB/sec = 1 msec
The time required to read and write is twice the sum of the seek and transfer time.
Total time = (5 msec + 4 msec) * 2 + 1 msec = 19 msec
b) half of 16 GB = 8 GB = 8000000 KB
number of read and writes = (8000000 KB of total file size/ 8 KB of average file size) * 2 = 2000000
Transfer rate = 8 MB/sec = 0.008 GB/sec
Transfer time = 8 GB ÷ 0.008 GB/sec = 1000 sec
Total time = (5 msec + 4msec) * 2000000 + 1000 sec = 19000 sec
This is the closest thing I could come up with since I don’t really know c++. (just so it’s easier maybe put the name of the programming language)
Answer:
Querying a SQL database.
Explanation:
SELECT Last Name, First Name
FROM EMPLOYEE
WHERE Employee ID IN
(SELECT EmployeeID
FROM PROPERTY_SERVICE
WHERE PropertyID IN
(SELECT PropertyID
FROM OWNED_PROPERTY
WHERE City = 'Newyork'));
Ctrl+z ............................................................
