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3 years ago

Find the interquartile range of the data. 4,6,4,2,9,1,12,7

Mathematics

1 answer:

mariarad [96]3 years ago

3 0

Answer:

Arrange: 1, 2, 4, 4, 6, 7, 9, 12.

(Q1) = (N + 1) × 1/4.

4 + 1 × 1/4 = 5/4

(Q3) = (N + 1) × 3/4.

6 + 1 × 3/4 = 21/4

So, IQR = Q3 - Q1

21/4 - 5/4 = 21 - 5/4
16/4 = 4

Explanation:

Do these simple steps to find IQR if any data:-

Order the data from least to greatest.
Find the median.
Calculate the median of both the lower and upper half of the data.
The IQR is the difference between the upper and lower medians.

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Answer:

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Step-by-step explanation:

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3 years ago

Hannah got a perfect score on 3 more spelling quizzes this quarter than last quarter . If she doubles the number of perfect quiz

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First, underline the key numbers

n=Perfect Quizzes last quarter

x=School record

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3 years ago

which has the greater volume? 1.a piece of paper rolled into a cylinder lengthwise, or the same piece of paper rolled into a cyl

marusya05 [52]

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3 years ago

Can i have help plzzzzz

leonid [27]

Answers:

Choice C) 1.5 + AB = 3.7

AB = 2.2 cm

====================================================

Explanation:

Segment AC can be cut into two smaller pieces AB and BC. The piece AB is of unknown length for now, while BC is 1.5 units long.

The expression AB+1.5 or 1.5+AB represents us adding those two smaller pieces together. Doing so will lead to the length of AC.

Therefore, 1.5 + AB = 3.7 is one valid equation to set up.

------------

To solve that equation, we subtract 1.5 from both sides to undo the addition operation done to AB.

1.5 + AB = 3.7

AB = 3.7 - 1.5

AB = 2.2

Notice how,

1.5 + AB = 1.5 + 2.2 = 3.7

to help confirm our answer.

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2 years ago