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3 years ago

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A tree casts a shadow 8ft long. A 6-ft man casts a shadow 4 ft long. The triangle formed by the tree and its shadow is similar t

o the triangle formed by the man and his shadow.How tall is the tree?

1 answer:

Gennadij [26K]3 years ago

6 0

Im not sure but it could be 192

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Given the rectangle ABCD, AB has a slope of 2/3, what is the slope of BC?

erastova [34]

Answer:

slope = - $\frac{3}{2}$

Step-by-step explanation:

note that BC is perpendicular to AB, hence the slope of BC is the negative reciprocal of the slope of AB

$m_{BC}$ = - $\frac{1}{2/3}$ = - $\frac{3}{2}$

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4 years ago

Use the ray tool to graph f(x)=−|x−2| .<br> (please include graph in answer.)

Fittoniya [83]

Answer:

The graph of $f(x)=-|x-2|$ is attached below.

Step-by-step explanation:

As the given function

$f(x)=-|x-2|$

Lets put some points to determine the graph.

For x = 0

$f(0)=-|0-2|=-2$

For x = 1

$f(1)=-|1-2|=-1$

For x = 2

$f(2)=-|2-2|=0$

For x = 3

$f(3)=-|3-2|=-1$

For x = 4

$f(4)=-|4-2|=-2$

Therefore, the graph of $f(x)=-|x-2|$ attached below.

<em>Keywords: absolute value</em>

<em> Learn more graphs and absolute value from brainly.com/question/11580077</em>

<em> #learnwithBrainly</em>

8 0

3 years ago

Find the distance between each pair of points (-2,3) , (-7, -7)

Fantom [35]

Answer:

D = $5\sqrt{5}$

Step-by-step explanation:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d= \sqrt{(-7-(-2))^2+(-7-3)^2} \\d= \sqrt{(-5)^2+(-10)^2} \\d= \sqrt{25+100} \\d= \sqrt{125} \\d= 5\sqrt{5}$

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4 years ago

Simplify each expression.

GrogVix [38]

Answer:

9. Let's simplify step-by-step.

Ans. 5x + 24 + 147

Combine Like Terms:

= 5x + 24 + 147

= ( 5x ) + ( 24 + 147 )

= 5x + 171

10. Let's simplify step-by-step.

Ans. 3x + ( 7x + 10 )

Combine Like Terms:

( 3x + 7x ) + 10

10x +10

11. Let's simplify step-by-step.

Ans. 5x + ( 2 + 3 )

5x + 5

12. 4 * 10

Ans. 40

13. 3 ( 12x )

Ans. 36x

14. 14r + 9y + 6x

Ans. 14r + 6x + 9y

Hope it helps

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6 0

3 years ago

A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,

Romashka-Z-Leto [24]

Answer:

radius x = 3 ft

height h = 23,8 ft

Step-by-step explanation:

From problem statement

V(t) = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c) = π*x²*h area of cylinder = area of base + lateral area

A(c) = π*x² + 2*π*x*h

V(h) = (2/3)*π*x³ area of hemisphere A(h) = (2/3)*π*x²

A(t) = π*x² + 2*π*x*h + (2/3)*π*x²

Now A as fuction of x

total volume 505 = π*x²*h + (2/3)*π*x³

h = [505 - (2/3)* π*x³ ] /2* π*x

Now we have the expression for A as function of x

A(x) = 3π*x² + 2π*x*h A(x) = 3π*x² + 505 - (2/3)π*x³

Taking derivatives both sides

A´(x) = 6πx - 2πx² A´(x) = 0 6x - 2x² = 0

x₁ = 0 we dismiss

6 - 2x = 0

x = 3 and h = [505 - (2/3)* π*x³]/2* π*x

h = (505 - 18.84) / 6.28*3

h = 23,8 ft

7 0

3 years ago