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2 years ago

I don’t understand the question and I can’t find anything in my notes to help

Mathematics

1 answer:

lara [203]2 years ago

7 0

Step-by-step explanation:

The problem states that you have a linear function so expect your equation to have this form:

y = mx + b

where m is the slope and b is the y-intercept. You are also given two points: P1(5, 6) and P2(14, 60). Use these points to solve for the slope m.

m = (y2 - y1) / (x2 - x1) = (60 - 6)/(14 - 5)

= 54/9 = 6

So our equation now becomes

y = 6m + b

To solve for b, plug in the values of P1:

6 = 6(5) + b ---> b = -24

Therefore, our equation is

y = 6m - 24

The rest of the points are

(8, 24)

(11, 42)

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3 years ago

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Find a ·<br> b. |a| = 80, |b| = 50, the angle between a and b is 3π/4.

mart [117]

Answer:

$a\cdot b=-2000\sqrt{2}$

Step-by-step explanation:

Given information: |a| = 80, |b| = 50, the angle between a and b is 3π/4.

We need to find the dot product a · b.

The formula of dot product is

$a\cdot b=|a||b|\cos \theta$

where, θ is the angle between a and b.

Substitute the given values in the above formula.

$a\cdot b=(80)(50)\cos (\frac{3\pi}{4})$

$a\cdot b=4000\cos (\pi-\frac{\pi}{4})$

$a\cdot b=-4000\cos (\frac{\pi}{4})$ $[\because \cos (\pi-\theta)=-\cos \theta]$

$a\cdot b=-4000\frac{1}{\sqrt{2}}$

$a\cdot b=-\frac{4000}{\sqrt{2}}$

Rationalize the above equation.

$a\cdot b=-\frac{4000}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}$

$a\cdot b=-\frac{4000\sqrt{2}}{2}$

$a\cdot b=-2000\sqrt{2}$

Therefore, the value of a · b is $a\cdot b=-2000\sqrt{2}$ .

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2 years ago

Read 2 more answers

Why the order of the coordinates does not matter when calculating length

Rudiy27

The formula for calculating length is:
$\sqrt{ (x_b-x_a)^{2} + (y_b-y_a)^{2} }$

We can also write $x_a - x_b$ or $y_a - y_b$
Why it does not matter?
Let's assume we have 2 numbers, a and b.
When we perform a subtraction:
$a-b$ , we get another number $c$
When we perform another subtraction:
$b-a$ , we get a number $-c$

When we raise $c$ or $-c$ to the power of 2, the result is the same, $c^{2}$ .

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3 years ago