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3 years ago

List the different parts of a credit report. Thanks in advance

Mathematics

1 answer:

luda_lava [24]3 years ago

4 0

Credit Score, Account Histories, Public Records, Personal Information, Inquiries

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I need the help as soon as possible

Minchanka [31]

Answer:

a is true

Step-by-step explanation:

its because 7+(-7) =0 so a is correct

7 0

3 years ago

Read 2 more answers

Product of (5 + a) and ( -5 + a ) is ......

lorasvet [3.4K]

Answer:

a^2 - 25.

Step-by-step explanation:

(5 + a)(-5 + a)

= -25 + 5a - 5a + a^2

= a^2 - 25.

4 0

3 years ago

1. How does the scope of practice help regulate the health care field?

Lubov Fominskaja [6]

Answer:

Scope of practice describes the procedures, actions, and processes that a healthcare practitioner is permitted to undertake in keeping with the terms of their professional license.

Step-by-step explanation:

By implementing the law which restricts certain people to work under what they excel they are low chances of making errors in their respective field . and this leads to increase in the proper medical treatment and this would regulate the health care field. suppose if a person with tooth pain comes to neurologist ,according to scope of practice restricted to treat him which results in the neurologist making error in treating dental problem is decreased and he might consult better dentist.

3 0

3 years ago

jake can carry 6 1/4 pounds of wood in from the barn. His father can carry 1 5/7 times as much as Jake. How many pounds can Jake

Studentka2010 [4]

It would be: 6 1/4 * 1 5/7
= 25/4 * 12/7
= 300/28 = 150/14 = 75/7

In short, Your Answer would be 75/7 or 10 5/7 Pounds

Hope this helps!

4 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago