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2 years ago

Match the reasons with the statements given.

Mathematics

2 answers:

pantera1 [17]2 years ago

8 0

Given: ABCD is a rhombus

To prove: DB bisects ∠ABC and ∠ADC (∠1=∠2 and ∠3=∠4)

Proof: In ΔADB and ΔCDB

AD=CD (sides of same rhombus)

DB=DB (common in both triangle)

AB=CB (sides of same rhombus)

∴ ΔADB ≅ ΔCDB by SSS congruence property.

Angle bisector: A line divide an angle into two equal part.

CPCT: Congruent part of congruence triangles.

Match the statements:-

ABCD is rhombus ⇒ Given
ΔADB≅ΔCDB ⇒ Diagonals of parallelogram make congruent Δ
∠1=∠2,∠3=∠4 ⇒ CPCTE
DB bisects ∠ABC and ∠ADC ⇒ Definition of angle bisector

Thus, Above matching is correct.

Alja [10]2 years ago

5 0

I believe the matching would be as follows;
1. ABCD is a rhombus -Given
2. Triangle ADB congruent to Triangle CDB- Diagonals of parallelogram make congruent triangles. The two triangles share a diagonal BD as their third side.
3. ∠1=∠2, ∠3=∠4 ; CPCTE
4. DB bisects ∠ABC and ∠ADC - definition of angle bisector

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What is f(5)? please answer

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f(x) is y, in which x is the independent variable

when x = 5, y = -8

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2 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

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2 years ago

To find the average of a student’s test scores, add the scores and divide by the number of tests. Suppose Ryan scored 85, 92, 88

Lilit [14]

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2 years ago

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A truck that can carry no more than 6500 lb is being used to transport refrigerators and upright pianos. Each refrigerator weigh

anyanavicka [17]

Answer:

Equation: 300x+425y= 6500 (if you assume that you would get an exact total)

Answer: Yes, 11 refridgerators and 9 pianos will overload the truck because 11x300=3,300 and 9x425=3,825 which in total equals 7,125, which is way too much for the truck.

An equation that works: 300(10)+425(8)=

Step-by-step explanation:

If each refrigerator is 300 pounds and we need to see if 11 would fit on the truck, multiply 300 times 11 which equals 3,300. Next repeat the same step but for the pianos… 425 times 9 which equals 3,825 now you add. You should get 7,125, meaning this ratio is way to large for the truck to carry.

Since this does not work we should try take away one of each. So let’s say the new rati is 10 refrigerators to 8 pianos. We would repeat the same steps from above. 10x300=3,000 8x425=3,400

If we add these, we get 6,400 so the final expression would be 300(10)+425(8)=6,400 which would be the closest the the most you can transport on the truck.

Sorry if this was not the answer you were looking for, I may have misinterpreted the question.

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Answer:

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