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Hitman42 [59]
3 years ago
13

there are seven performers who will present their comedy acts this weekend at a comedy club. How many different ways are there t

o schedule their appearance?
Mathematics
1 answer:
charle [14.2K]3 years ago
4 0
The amount of different ways possible can be shown by 7!=5040 Im pretty sure.
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Solve for x 3(x-1)-5=-3(-6x+4)-5x
Romashka [77]

Answer: x= 2/5

Step-by-step explanation:

3(x-1) - 5 = -3(-6x+4) - 5x

Remove parenthesis

3x-3-5=18x-12-5x

Calculate and combine like terms

3x-8=13x-12

Move terms

3x-13x=-12+8

add like terms

-10x=-4

divide both sides ny -10

x=2/5

5 0
3 years ago
8) There are 2116 students in a school .In how many equal rows and columns can they be arranged for a drill display?
svetoff [14.1K]

Answer:

46

Explanation:

root of 2116

=46×46

Therefore 46 columns and 46 rows

8 0
3 years ago
Read 2 more answers
When an inequality is in slope-intercept form, what is the form?*
horsena [70]

Answer:

y=mx+b

Step-by-step explanation:

this is slope intercept form but you must fill in the letters with numbers

3 0
3 years ago
Can you help me with any of them?
zhenek [66]
For number 4 you do x + 19 = 90
90 - 19 = 71 so x = 71
6 0
3 years ago
Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Maru [420]
A) System of inequalities

Income from babysitting: 6x
Income from tutoring: 10y

Goal for this week: at least $ 75 => 6x + 10y ≥ 75
Number of hours: maximum $20 => x + y ≤ 20

x and y have to be zero or positvie => x≥0 and y ≥ 0

Answer of part A.

6x + 10y ≥ 75
x+y ≤ 20
x ≥ 0
y ≥ 0

Part B. Graph

The solution is a region closed by 4 lines and you can find it in the file attached.

In that graph:

1) the line x + y = 20 is the upper limit
2) the line 6x + 10 y = 75 is the lower incclined line
3) y = 0 is the botton horizontal line it is the x-axis
4) x = 0 is the left vertical line, in is the y-axis

Part C.

Use, for example the point (7,10).

It is in the region of the graph limited by the above equations.

It implies:

Number of hours worked = 7 + 10 = 17 which is less than 20.

Income: 6(7) + 10(10) = 42 + 100 = 142, which is greater than 75

Of course, both are greater than 0.

In this way we proved that the point (7,10) is a true solution for the model.






Download pdf
8 0
3 years ago
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