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3 years ago

Evaluate (will give brainliest)

Mathematics

2 answers:

Natalka [10]3 years ago

7 0

Answer:

Step-by-step explanation:

1. X/2 when x = 1/2

Putting value of x in the equation

1/2 /2 = 0.25

2. 2x2 - 8 when x = 3

2(3)2 - 8

= 2(9) - 8

= 18 - 8 = 10

3. 4(x - 7)3 + 5 when x = 9

4 (x3 - 21x2 + 147x - 343) + 5

Putting value of x

4((9)3 - 21(9)2 + 147(9) - 343) + 5

4(729 - 1701 + 1323 - 343) + 5

4(8) + 5

= 32 + 5 = 37

katrin2010 [14]3 years ago

6 0

Answer:

1. 0.25

2. 208

3. 517

Step-by-step explanation:

Number 1.

0.5/2

= 0.25

number 2.

2(3)^3-8

6^3 - 8

216-8

= 208

Number 3.

4(9-7)^3 +5

4(2)^3+5

8^3+5

= 517

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Step-by-step explanation:

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4 years ago

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3 years ago

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A weather satellite I'm circular orbit around earth completes one orbit every 5 hours. The radius of earth is about 6,400 km and

balu736 [363]

To solve this problem you must apply the proccedure shown below:

1. You have that:

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3 years ago

Vector question. Let v=<-2,1> u=<3,-5> , find:

lyudmila [28]

Answer:

1. ) $\vec {v}.\vec{u}= -11$

2.) The angle between v and u is 147.52°.

Step-by-step explanation:

Given:

$\vec {v}= ( -2 , 1 )\\\vec {u}= ( 3 , -5 )$

To Find:

1. $\vec {v}.\vec{u}= ?$

2. $\theta = ?$

Solution:

$\vec {v}.\vec{u}$ is scalar product given as,

$\vec {v}.\vec{u}=|\vec {v}||\vec {u}|\cos \theta$

$|\vec {v}|=|(-2, 1)|=\sqrt{(-2)^{2} +1^{2}}=\sqrt{5}\\|\vec {u}|=|(3, 5)|=\sqrt{(3)^{2} +(-5)^{2}}=\sqrt{34}$

$\vec {v}.\vec{u}=(-2i +j).(3i-5j)\\$

Here only i.i = j.j =1 and i.j = j.i = 0

∴ $\vec {v}.\vec{u}=(-2\times 3 +1\times -5)\\\vec {v}.\vec{u}=-6-5=-11 \\$

Now, Substituting the above values we get

$-11=\sqrt{5}\times \sqrt{34}\cos \theta\\ \cos \theta=\frac{-11}{\sqrt{170}} \\ \cos \theta =-0.84366\\\therefore \theta =cos^{-1}(-0.84366)\\\therefore \theta =147.52\°$

As it is negative mean $\theta$ is in Second Quadrant Because Cosine is negative in Second Quadrant.

1. ) $\vec {v}.\vec{u}= -11$

2.) The angle between v and u is 147.52°.

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3 years ago