According to CollegeBoard.org:
<u>Answer</u>: "To estimate the probability of observing a value as extreme as pˆ given p."
<u>Explanation</u>: "The test statistic for a one-sample z-test is the distance, in units of standard deviations, between the statistic and the given parameter. From that distance, probabilities (a p-value) can be calculated and a claim can be assessed."
Answer:
domain = all real numbers
Step-by-step explanation:
domain is the x axis
its asking what it goes to but if they have arrows then forever
The answer is B. 8x+6. You multiple 3 and x+4 then combine like terms
Answer:
The critical value is T = 1.895.
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 6
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.895, which is the critical value.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159
The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Answer: 0.14
Step-by-step explanation:
1) Find the total #of seniors. To do this add up 25+5+5 = 35.
2)Since we know the number of seniors that work just do 5/35. This simplifies to 0.14 rounded to the nearest hundreth.