3 years ago

A rectangular park is

1 answer:

4 0

To do this, you have to know the original perimeter of this park (490 yds) and the area (14,500 yds squared)
A park with the same perimeter (490 yds) but smaller area (9,750 yds squared) is 195ydsx50yds

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Fittoniya [83]

Answer:

2 $\sqrt{34}$

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (4, - 6)

d = $\sqrt{(4+2)^2+(-6-4)^2}$

= $\sqrt{6^2+(-10)^2}$

= $\sqrt{36+100}$

= $\sqrt{136}$ = $\sqrt{4(34)}$ = $\sqrt{4}$ × $\sqrt{34}$ = 2 $\sqrt{34}$

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