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shepuryov [24]
3 years ago
11

Which of these choices show a pair of equivalent expression? Check all that apply.

Mathematics
2 answers:
padilas [110]3 years ago
8 0

Answer:

C and D

Step-by-step explanation:

using the rules of exponents

A

125^{3/7} = \sqrt[7]{125^3} ≠ \sqrt[3]{125^7}

B

(\sqrt{12})^7 = 12^{7/2} ≠ 12^{1/7}

C

(\sqrt{4})^5 = 4^{5/2} ← correct

D

(\sqrt{8})^9 = 8^{9/2} ← correct


sasho [114]3 years ago
7 0

Answer:  The correct options are

(C) 4^\frac{5}{2}~~\textup{and}~~(\sqrt{4})^5.

(D) 8^\frac{9}{2}~~\textup{and}~~(\sqrt{8})^9.

Step-by-step explanation:  We are to select the correct pairs that shows equivalent expressions.

We will be using the following property of exponents and radicals :

<u>(\sqrt[b]{x})^a=x^\frac{a}{b}.</u>

<em><u>Option (A) :</u></em>

The given expressions are

(\sqrt[3]{125})^7~~\textup{and}~~125^\frac{3}{7}.

We have

(\sqrt[3]{125})^7=125^\frac{7}{3}\neq 125^\frac{3}{7}.

So, the expressions are not equivalent and option (A) is incorrect.

<em><u>Option (B) :</u></em>

The given expressions are

12^\frac{1}{7}~~\textup{and}~~(\sqrt{12})^7.

We have

12^\frac{1}{7}=\sqrt[7]{12},\\\\(\sqrt{12})^7=12^\frac{7}{2}.

So,

12^\frac{1}{7}\neq (\sqrt{12})^7.

Therefore, the expressions are not equivalent and option (B) is incorrect.

<em><u>Option (C) :</u></em>

The given expressions are

4^\frac{5}{2}~~\textup{and}~~(\sqrt{4})^5.

We have

(\sqrt{4})^5=4^\frac{5}{2}

Therefore, the expressions are equivalent and option (C) is correct.

<em><u>Option (D) :</u></em>

The given expressions are

8^\frac{9}{2}~~\textup{and}~~(\sqrt{8})^9.

We have

(\sqrt{8})^9=8^\frac{9}{2}

Therefore, the expressions are equivalent and option (D) is correct.

Thus, (C) and (D) are the correct options.

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Answer:

1.        t = 0.995 s

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Step-by-step explanation:

First we have to look at the following formula

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then we work it to clear what we want

Vo + gt = Vf

gt = Vf - Vo

t = (Vf-Vo)/g

Now we have to complete the formula with the real data

Vo = 32 ft/s      as the statement says

Vf = 0     because when it reaches its maximum point it will stop before starting to lower

g = -32,16 ft/s²        it is a known constant, that we use it with the negative sign because it is in the opposite direction to ours

t = (0 ft/s - 32 ft/s) / -32,16 ft/s²

we solve and ...

t = 0.995 s

Now we will implement this result in the following formula to get the height at that time

h = (Vo - Vf) *t /2

h = (32 ft/s - 0 ft/s) * 0.995 s / 2

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3 years ago
Help! Please:) Amd Thank you!!!
Mrrafil [7]
They get 2/3 because 2 divided by 3=2/3.
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3 years ago
What is the solution to the system of equations? -2x + y = -5 3x – 2y = 12 A) (3, 1) B) (6, 3) C) (-2, -9) D) (-2, -1)
max2010maxim [7]

Answer:

The correct answer is D) (-2, -1)

Step-by-step explanation:

In order to solve this system of equations, start by multiplying the entire first equation by 2. Then add the two equations together. This will get the y's to cancel and allow you to solve for x.

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3 years ago
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My name is Ann [436]
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