Answer:
Step-by-step explanation:
its the first one
Answer:
The given line segment has a midpoint at (−1, −2).
On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1).
What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?
y = −4x − 4
y = −4x − 6
y = One-fourthx – 4
y = One-fourthx – 6
y = Three-halvesx + 1
The product of (x1)^2 is 20
Answer: ![\sin \theta=\frac{-45}{53}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D%5Cfrac%7B-45%7D%7B53%7D)
Step-by-step explanation:
Since we have given that
![\cos\theta=\frac{28}{53}](https://tex.z-dn.net/?f=%5Ccos%5Ctheta%3D%5Cfrac%7B28%7D%7B53%7D)
And we know that θ is in the Fourth Quadrant.
So, Except cosθ and sec θ, all trigonometric ratios will be negative.
As we know the "Trigonometric Identity":
![\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}](https://tex.z-dn.net/?f=%5Ccos%5E2%5Ctheta%2B%5Csin%5E2%5Ctheta%3D1%5C%5C%5C%5C%5Csin%20%5Ctheta%3D%5Csqrt%7B1-%5Ccos%5E2%5Ctheta%7D%5C%5C%5C%5C%5Csin%20%5Ctheta%3D%5Csqrt%7B1-%28%5Cfrac%7B28%7D%7B53%7D%29%5E2%7D%3D%5Csqrt%7B%5Cfrac%7B53%5E2-28%5E2%7D%7B53%5E2%7D%7D%5C%5C%5C%5C%5Csin%20%5Ctheta%3D%5Csqrt%7B%5Cfrac%7B2025%7D%7B53%5E2%7D%7D%5C%5C%5C%5C%5Csin%20%5Ctheta%3D%5Cfrac%7B45%7D%7B53%7D)
It must be negative due to its presence in Fourth quadrant.
Hence, ![\sin \theta=\frac{-45}{53}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D%5Cfrac%7B-45%7D%7B53%7D)