Answer:
this is my another account on brainly
Y = 3x^2 - 3x - 6 {the x^2 (x squared) makes it a quadratic formula, and I'm assuming this is what you meant...}
This is derived from:
y = ax^2 + bx + c
So, by using the 'sum and product' rule:
a × c = 3 × (-6) = -18
b = -3
Now, we find the 'sum' and the 'product' of these two numbers, where b is the 'sum' and a × c is the 'product':
The two numbers are: -6 and 3
Proof:
-6 × 3 = -18 {product}
-6 + 3 = -3 {sum}
Now, since a > 1, we divide a from the results
-6/a = -6/3 = -2
3/a = 3/3 = 1
We then implement these numbers into our equation:
(x - 2) × (x + 1) = 0 {derived from 3x^2 - 3x - 6 = 0}
To find x, we make x the subject of 0:
x - 2 = 0
OR
x + 1 = 0
Therefore:
x = 2
OR
x = -1
So the x-intercepts of the quadratic formula (or solutions to equation 3x^2 - 3x -6 = 0, to put it into your words) are 2 and -1.
We can check this by substituting the values for x:
Let's start with x = 2:
y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}
For when x = -1:
y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
= 3 + 3 - 6
= 0 {so when x = -1, y = 0, which is correct}
Answer:
B. Quadrant 1
Step-by-step explanation:
Dilation about the origin multiplies each coordinate by the dilation factor. If the dilation factor is positive, the signs of the coordinates are unchanged, so the point they specify remains in the same quadrant.
If the dilation factor is negative, the point is reflected across the origin at the same time it is subject to dilation. That is, both coordinate signs are changed.
For a dilation factor of -2, the point L becomes ...
L(-2, -3) ⇒ L' = -2L = L'(4, 6) . . . . . in quadrant I
Answer:
Good for her!
Step-by-step explanation:
If the fraction is for example 1/4, try to graph it at before the half by a little.