Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:
Rewrite the integrand:
The integral is then
Answer:
The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.
Step-by-step explanation:
Given:
Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.
Now, to find the weight of each animal:
Let the cat's weight be
And the kitten weight =
Total weight of cat and kitten = 18 pounds.
Now, to set an equation to get the weight of each animal:
<em>Multiplying both sides by 2 we get:</em>
<em /><em />
<em>Adding both sides by 6 we get:</em>
<em /><em />
<em>Dividing both sides by 3 we get:</em>
<em /><em />
<em>The weight of cat = 14 pounds.</em>
Substituting the value of to get the kitten's weight:
<em>The kitten's weight = 4 pounds.</em>
Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.
Answer:
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352 . If you multiply 16 by 22 it will give u an answer of 352
Answer:
<h2>x= 37/16</h2><h3>
y=199/8</h3>
Step-by-step explanation:
1....y=11+6x
-77-2x+3y=-7
replace y by ..1..
so -77-2x+3(11+6x)=-7
-77-2x+33+18x=-7
-44+16x=-7
16x=37
y=11+6x
replace x by 37/16
y=11+6*37/16
y=199/8