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3 years ago

If Ryan slices the pyramid parallel to any side of the pyramid other than the base, what will the shape of the cross section be?

Mathematics

2 answers:

Anon25 [30]3 years ago

6 0

<span>A cross section parallel to any side other than the base that has a shape of a trapezoid.</span>

kupik [55]3 years ago

4 0

Answer with explanation:

A pyramid is a three dimensional solid , having base in the shape of any polygon and other faces are in the shape of triangle meeting at a point.

So, if you cut the pyramid , parallel to any side of the pyramid other than the base you will obtain

A pyramid having same base as original pyramid, that will be the top view but front view will be of trapezoid.

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What is 20.30 - 19.70 and what are the solving steps?

DIA [1.3K]

Answer

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Step-by-step explanation:

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3 years ago

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How does adding a solute ( use only one - salt or sugar) effect the time of water to change from a liquid to a solid?

Kruka [31]

Answer:

adding salt makes the water freeze slower and evaporate slower too.

Step-by-step explanation:

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3 years ago

Find the factors and the greatest common factor 375,66,333

lyudmila [28]

Answer:

the greatest common factor is 3

Step-by-step explanation:

375: 1, 3, 5,11, 15, 25, 75, 125, 375

66: 1, 2, 3, 6, 11, 22, 33, 66

333: 1, 3, 9, 37, 111, 333

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3 years ago

Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

4 0

2 years ago

If a baby weighed 3 and 3/8 how many more pounds would it have to gain to reach 5 1/2 pounds

Volgvan

First, get common denominators
At the same time, turn these into mixed numbers
27/8 + x = 44/8
Subtract 27/8 from both sides
x = 2 1/8 pounds
Let’s x be how many more pounds the baby needs

6 0

3 years ago