Please help i'm timed!!!!

Mathematics

1 answer:

MrRissso [65]3 years ago

4 0

Answer:

The second one

Step-by-step explanation:

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Factor completely 4u^2-28u+49

icang [17]

$\bold{Answer}$

$\boxed{\bold{\left(2u-7\right)^2}}$

$\bold{Explanation}$

$\bold{Factor: \ 4u^2-28u+49}$

$\bold{---------------------}$

$\bold{Rewrite \ 4u^2-28u+49: \ \left(2u\right)^2-2\cdot \:2u\cdot \:7+7^2}$

$\bold{\left(2u\right)^2-2\cdot \:2u\cdot \:7+7^2}$

$\bold{Apply \ Perfect \ Square \ Formula \ \left(a-b\right)^2=a^2-2ab+b^2: \ a=2u,\:b=7}$

$\bold{\left(2u-7\right)^2}$

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3 0

3 years ago

Read 2 more answers

Two mathematical questions attached below.

BartSMP [9]

Answer:

See below

Step-by-step explanation:

$9.( {m}^{3} {n}^{5} )^{ \frac{1}{4} } \\ = m^{\frac{3}{4}}n^{\frac{5}{4}}\\ \\ 10. \sqrt[5]{ \sqrt[4]{x} } \\ = \sqrt[5]{ {x}^{ \frac{1}{4} } } \\ = {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} } \\ = {x}^{ \frac{1}{4} \times \frac{1}{5} } \\ = {x}^{ \frac{1}{20} } \\ \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } } \\ = \sqrt[5]{ {a}^{ \frac{2}{3} } } \\ = {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} } \\ = {a}^{ \frac{2}{3} \times \frac{1}{5} } \\ = {a}^{ \frac{2}{15} }$