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Charra [1.4K]
3 years ago
6

0.4 repeating as a fraction for a mixed number

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

Step-by-step explanation:

1.Rewrite the decimal number as a fraction with 1 in the denominator

2.Multiply to remove 1 decimal places. Here, you multiply top and bottom by 101 = 10

3.Find the Greatest Common Factor (GCF) of 4 and 10, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 2,

so the answer is

0.4= 2/5

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Lee is making cookies and the recipe calls for 3/4 c. of chocolate chips. If she wants to make 2/3 of the recipe, what fraction
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3/4×2/3=1/2 that is the answer

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What value of s makes the following equation true?<br><br> s3 = −343
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-144.33333 or -14 1/3
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If ac =14 find the value of x then find ab and bc
Igoryamba

Answer:

If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.

Step-by-step explanation:

AB=x

BC = 2x + 2BC=2x+2

AC =14AC=14

Required

Determine x, AB and BC.

Since B is between A and C;

AB + BC = ACAB+BC=AC

Substitute x for AB; 2x + 2 for BC and 14 for AC

x + 2x + 2 = 14x+2x+2=14

3x + 2 = 143x+2=14

Collect Like Terms

3x = 14 - 23x=14−2

3x = 123x=12 '

x = \frac{12}{3}x=

3

12

x = 4x=4

Substitute 4 for x in

AB = xAB=x

BC = 2x + 2BC=2x+2

AB = 4AB=4

BC = 2(4) + 2BC=2(4)+2

BC = 8 + 2BC=8+2

BC = 10BC=10

3 0
2 years ago
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

4 0
1 year ago
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