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2 years ago

What expression is equvialent to -6 (-2/3 + 2x)?

Mathematics

1 answer:

finlep [7]2 years ago

6 0

Answer:

the answer is −

1 2 + 4

Step-by-step explanation:

i hope this helps

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A child's tent can be modeled as a pyramid with a square base whose sides measure 60 inches and whose height measures 84 inches.

IgorC [24]

Answer:

The volume of the tent is $100,800\ in^{3}$

Step-by-step explanation:

we know that

The volume of the square pyramid (child's tent) is equal to

$V=\frac{1}{3}b^{2}h$

we have

$b=60\ in$

$h=84\ in$

substitute

$V=\frac{1}{3}(60^{2})(84)=100,800\ in^{3}$

5 0

3 years ago

Read 2 more answers

The scale on a map of Virginia shows that 1 inch represents 20 miles the actual distance from Richmond Virginia to Washington DC

DedPeter [7]

Answer:

5.5 inches

Step-by-step explanation:

Proportions:

1 inch ⇔ 20 miles

W inch ⇔ 110 miles

W = 110*1/20

W = 5,5 inch

7 0

2 years ago

Emily needs to buy 2.5 pounds of pecans for a pie.If pecans cost 1.50 per pound how much will Emily pay for pecans?

AleksandrR [38]

Answer:

3.50

Step-by-step explanation:

1.50 x 2 = 3 And their is .50 left so half of 1 pound is .50 which is 3+50=3.50

If this helped please make me brainliest :)

7 0

2 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$