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Solnce55 [7]
3 years ago
9

2 times what equals 36

Mathematics
1 answer:
yarga [219]3 years ago
7 0
2 times 18 equals 36... Did I do a good job answering your question?? If so, brainliest, please. :)
You might be interested in
Which number when rounded to the nearest tenth is the largest number? A) 5.47 B) .723 C) 23.409 D) 5.89
kifflom [539]

Answer:

C)

Step-by-step explanation:

5.47 = 5.5

0.723 = 0.7

23.409 = 23.4

5.89 = 5.9

7 0
3 years ago
Can you chick are those right
Maksim231197 [3]
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4 0
2 years ago
The cost T, in dollars, of tuition and fees at Addison Technical College is $125 per credit plus an $85 registration fee. How ma
Jet001 [13]

Answer:

8

Step-by-step explanation:

125 + 85=210.

210 * 8 = 1680.

Therefore, the answer is 8.

6 0
2 years ago
What is the cost of six filters if eight cost 39.92
nasty-shy [4]
The cost of six filters is 29.94 since each filter costs 4.99
8 0
3 years ago
Question 1,2, and 3 how do i factor those? Can you show the work and explain how?
DiKsa [7]

1: 3n^{2}+9n+6

notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

3(n^{2} +2n+n+2)

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

2: 28+x^{2} -11x

So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

x^{2} -4x-7x+28

now we can factor out x from the first expression and -7 from the second

x(x-4)-7(x-4)

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to x^{2} -11x+28

3: 9x^{2} -12x+4

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as 3^{2} and 4 as 2^{2}, the equation becomes

3^{2} x^{2} -12x+2^{2}

now that 3^{2} x^{2} is ugly so it can be turned into (3x)^{2}

and -12x can be rewritten as -2*3x*2

so our equation now looks like (3x)^2-2*3x*2+2^{2}

There's a rule that says a^{2} -2ab+b^{2} = (a-b)^{2}

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

(3x-2)^2

5 0
2 years ago
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