We can write this in math as x+y+z=104, x=y-6, and z=3y
Because we already know what x and z are in terms of y, we can substitute our values for x and z into the first equation. This now looks like (y-6) + y + (3y) = 104. Now we can simplify our equation to find our value for y.
y-6 + y + 3y = 104 simplifies to 5y - 6 = 104, then 5y=110, and finally y=22.
Now that we know our value for y we can find our values for x and z by substituting our value for y into the other two equations.
The second equation x = y-6 can be simplified as x = 22 - 6 and further simplified as x = 16.
The third equation z = 3y can be written as z = 3(22) or z = 66.
Our three numbers are 16, 22, and 66. Hope this helps you!
Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
First you subtract 242 from 1250 which gives you 1080. Then you divide it by 8 which gives you 126. Multiply this value by 3 and this shows that Haryati received $378. Hope this is helpful.
Answer: see Explanation
Step-by-step explanation:
THE GAINEY'S:
Recursive Formula :
A1 = $10
An = An-1 + $10
A2 = $10 + $10 = $20
Where n = day of the month
Explicit formula :
y = a + b(c - 1)
WHERE:
y = final amount
initial amount = a
Increment on initial amount = b
Day of the month = c
THE ARNOLD'S :
Recursive formula:
First day of the month (A1) = $10
An = 2(An-1)
A2 = 2(A1) = 2(10) = $20
A3 = 2(A2) = 2(20) =$40
Explicit formula:
y = a(b)^c
Where :
y = final amount
initial amount = a
Increment on initial amount = b
Day of the month = c
Answer:
7
Step-by-step explanation:
8x-2y=48, replace y with 4, 8x-2(4)=48, multiply, 8x-8=48, add 8 to both sides to remove the -8, 8x=56 and finally divide by 8 to remove 8 from x, x=7.
