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3 years ago

Determine whether the following sequence is arithmetic, geometric, or neither.

Mathematics

2 answers:

harkovskaia [24]3 years ago

6 0

Answer:

Step-by-step explanation:

belka [17]3 years ago

4 0

Answer:

1,4,9,16

$\frac{t2}{t1} = \frac{4}{1} \: \: \: \: \geometric$

Step-by-step explanation:

you first divide the second term by the first term

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El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan

Dovator [93]

Answer:

El coste de producir un juego de vídeo es de 125 dólares.

Step-by-step explanation:

(This exercise is written in Spanish and is incomplete. Complete statement will be presented below)

El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan 850 dólares . Si suponemos un modelo lineal como el descrito anteriormente , determine:

¿Cuál es el costo de producir un juego de vídeo?

(Explanation will be held in Spanish)

El modelo lineal es un polinomio de primer orden de la forma:

$y = a\cdot x + b$

Donde:

$x$ - Variable independiente (eje x - Cantidad de juegos de vídeo producidos - Adimensional)

$y$ - Variable dependiente (eje y - Coste de producción de juegos de vídeo - Dólares)

$a$ - Pendiente de la función.

$b$ - Intercepto en el eje y.

Dados los dos costes para dos cuotas distintas de producción, se construye el siguiente sistema de ecuaciones lineales:

$10\cdot a + b = 350$

$30 \cdot a + b = 850$

Se resuelve el sistema con algo de manipulación algebraica:

$(30\cdot a + b) - (10\cdot a + b) = 850 - 350$

$20 \cdot a = 500$

$a = 25$

Luego:

$b = 850 - 30\cdot a$

$b = 100$

La ecuación lineal es:

$y = 25\cdot x +100$

Finalmente, el coste de producir un juego de vídeo es:

$y = 25 \cdot (1) + 100$

$y = 125$

El coste de producir un juego de vídeo es de 125 dólares.

7 0

4 years ago

Suppose 56% of students chose to study Spanish their senior year, and that meant that there were 98 such students. How many stud

Varvara68 [4.7K]

The number of students who chose not to study Spanish in their senior year is 124.

In mathematics, a percentage is a number or ratio that can be expressed as a fraction of 100. If we have to calculate percent of a number, divide the number by the whole and multiply by 100. Hence, the percentage means, a part per hundred. The word per cent means per 100. It is represented by the symbol “%”.

Given that

56% Students studied Spanish, which means 44% did not study Spanish.

In mathematics, a ratio shows how many times one number contains another.

Hence if the ratio is:

56 : 44 = 14:11

Then, the number of students who did not study Spanish is:

(14/11)×98 = 124.

Therefore the correct answer is 124.

To know more about probability.

visit-: brainly.com/question/11234923

#SPJ1

5 0

2 years ago

determine the equation of the parabola (simplified) with roots -3+sqrt6 and -3-sqrt6, and passing through the point (-1,4)

klio [65]

Given:

Roots:

$\begin{gathered} -3+\sqrt[]{6} \\ -3-\sqrt[]{6} \end{gathered}$

Point: (-1,4)

To determine the equation of the parabola with the given roots and point, we find the missing values first.

Since the roots are given, we can say that the equation is:

$y=a(x+3-\sqrt[]{6})(x+3+\sqrt[]{6})$

Next, we expand the terms.

$y=a(x^2+6x+3)$

Then, we plug in x= -1, and y=4 into the equation to get the value of a.

$\begin{gathered} y=a(x^2+6x+3) \\ 4=a((-1)^2+6(-1)+3) \\ \text{Simplify and rearrange} \\ 4=a(-2) \\ a=\frac{4}{-2} \\ a=-2 \end{gathered}$

So,

$undefined$

6 0

2 years ago

which of the following statements best describes the domain of the functions sine and arcsin? a) sine domain is all real numbers

netineya [11]

Sine can take any value while arc sin can only take values fom -1 to 1.
Therefore, sine domain is all real numbers; arcsin domain is restricted.

4 0

4 years ago

Taylor has $32000 a part of which he invested at 5% and the remainder at 3%. His annual return on each investment is the same. A

ki77a [65]

Taylor have to invest the total money at 3.75%

Step-by-step explanation:

Let the part of money invested at 5% be 'a' and the part of money invested at 3% be (32000-a).

To find (a) :

The annual income for both the 5% and 3% investment is equal.

Interest= (amount x rate of interest x time) /100

Interest for 5% rate on investment

Interest = (a x 5 x 1) /100

Interest for 3% rate on investment

Interest = [(32000-a) x 3 x 1]/100

Both the interests are equal so equate both the equations.

(a x 5 x 1) /100 = [(32000-a) x 3 x 1] /100

5a = (32000-a) 3

5a = 96000-3a

8a = 96000

a = 96000/8

a = 12000

32000-a = 32000-12000

= 20000

The amount invested at 5% is $12000 and invested $20000 at 3%

Interest = (12000 x 5 x 1) /100

= 60000/100

= $600

Interest = (20000 x 3 x 1) /100

= 60000/100

= $600

Total interest = $1200

To find the rate at which the total money is to be invested to get the same annual income.

1200 = (32000 x rate x 1) /100

1200 x 100 = 32000 x rate x 1

120000 = 32000 x rate

120000/32000 = rate

Rate = 3.75%

Taylor have to invest the total money at 3.75% to get the same annual income

4 0

3 years ago