Answer:
Step-by-step explanation:
a+2a+a+10=180
4a=180-10
4a=170
a=42.4°
2a=42.5*2=85°
a+10=42.5+10=52.5°
you simply have to add all of the numbers together, so it'll be 2+5+12+7+1 or 27, therefore the answer is B
The bearing of the plane is approximately 178.037°. ![\blacksquare](https://tex.z-dn.net/?f=%5Cblacksquare)
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that
,
,
and
, then the resulting vector is:
![\vec v = 239 \cdot (\sin 180^{\circ}, \cos 180^{\circ}) + 10\cdot (\sin 53^{\circ}, \cos 53^{\circ})](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20239%20%5Ccdot%20%28%5Csin%20180%5E%7B%5Ccirc%7D%2C%20%5Ccos%20180%5E%7B%5Ccirc%7D%29%20%2B%2010%5Ccdot%20%28%5Csin%2053%5E%7B%5Ccirc%7D%2C%20%5Ccos%2053%5E%7B%5Ccirc%7D%29)
![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (
), in degrees, by the following <em>trigonometric</em> expression:
(3)
![\theta = \tan^{-1}\left(-\frac{7.986}{232.981} \right)](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ctan%5E%7B-1%7D%5Cleft%28-%5Cfrac%7B7.986%7D%7B232.981%7D%20%5Cright%29)
![\theta \approx 178.037^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%20178.037%5E%7B%5Ccirc%7D)
The bearing of the plane is approximately 178.037°. ![\blacksquare](https://tex.z-dn.net/?f=%5Cblacksquare)
To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078
8.8 miles with 132 gallons of gas. You do 132 divided by 15 to get 8.8.
The surface area of a cube is:
A=6s^2 (It is just the area of 6 sides (squares) all having an area of s^2)
A=7.2^3=373.248 ft^3