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mina [271]
3 years ago
14

3x-8y=24 y=x-8 Please show work

Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer:

x = 8, and y = 0

Step-by-step explanation:

We can solve this by taking y as (x-8), as it states there.

Since y is equal to x-8, we can rearrange the system of equations into one single equation.

We can multiply y by 8, as it shows in the first equation, which is something like 8x-64.

Since it is a negative 8 being multiplied by y, it would be the inverse of 8x-64, which is -8x+64.

We can now organize our equation here.

3x - 8x + 64 = 24.

We can use subtraction property of equality by subtracing 64 from both sides to get rid of it.

We will get something like:

3x - 8x + 64 - 64 = 24 - 64.

Simplify by solving like terms like the x value and the integers.

-5x = -40

Divide both sides with division property of equality:

-5/5x = -40/5

x = 8

We can then plug the 8 back into x, lets use the second equation because I'm lazy and it looks the easiest to solve for.

y = (8) - 8

y = 0

Therefore, x = 8, and y = 0.

In-s [12.5K]3 years ago
4 0

Answer:

3x - 8y = 24   --------(1)

y = x - 8  ---------(2)

substitute  y in (1)

3x - 8( x - 8) = 24

3x - 8x + 64 = 24

-5x = 24 - 64

-5x = -40

5x = 40

x= 8

substitute x in (2)

y = 2 - 8

y = - 6

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Step-by-step explanation:

Subtract second number from the first number.

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Hence, 154 is larger than 27 by 127.

b. 25 and 12

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Question 8
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we are given

system of equations

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3x-2y=31

Second equation is

3x+2y=-1

now, we can find augmented matrix

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now, we can change it into reduced row echelon form

step-1: multiply the 1st row by 1/3

A=\begin{pmatrix}1&-2/3&31/3\\ 3&2&-1\end{pmatrix}

step-2:add -3 times the 1st row to the 2nd row

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step-3:multiply the 2nd row by 1/4

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