Answer:
The area of the region between the graph of the given function and the x-axis = 25,351 units²
Step-by-step explanation:
Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15
If 'f' is a continuous on [a ,b] then the function
By using integration formula
Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]
<em>On integration , we get</em>
= 
= 
After simplification and cancellation we get
= 
on calculation , we get
= 
On L.C.M 15
= 
= 25 351.2 units²
<u><em>Conclusion</em></u>:-
<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>
Answer:
8. 8.80
9. 90
Step-by-step explanation:
Question 8: Use the Pythagorean formula
DE² = DF²+EF²
EF² = DE² - DF²
= 16.2² - 13.6²
= 77.48
EF = √77.48 = 8.80 (Answer)
Question 9: Use the Cosine Rule
GI² = GH² +HI² - 2·GH·HI·Cos ∠GHI
= 60² + 42² - 2·60·42·Cos 123
= 3600 +1764 - (-2744.98)
= 8108.98
GI = √8108.98 = 90
Answer:
Step-by-step explanation:
Here are the 3 answers you needed :)!!!
Answer:
Step-by-step explanation:
You are to assume in both problems that the two triangles are similar. That is a very dangerous assumption -- especially in later math classes. But in this case, there is no other way to do the problem. The two sets of triangles look like they are proportional. So set up two ratios that are = to each other
On the left
long side small triange / long side large triangle = base small triangle / base large triangle
On the right
hypotenuse/longest leg = hypotenuse / longest leg.
Problem A
Set up the similar Proportion
5/40 = x/20 Cross Multiply
40x = 20*5
40x = 100 Divide by 40
x = 100/40
x = 2.5
Problem B
Again set up the similar triangle proportion
15/10 = x/2 Multiply by 2
15*2/10 = x
3 = x
