Determine whether the graph represents a linear or nonlinear function.

Mathematics

2 answers:

liberstina [14]2 years ago

6 0

Answer:

linear

Step-by-step explanation:

Because it is a straight line.

IgorLugansk [536]2 years ago

5 0

The graph represents a linear function, because the graph is a line.

Linear basically means straight line. If you look at the line, it always goes left once and up once and this is always the same. This means the graph follows the equation of y = mx + c and so is linear. In this case, the equation is y = -x + 1

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A daily mail is delivered to your house between 1:00 p.m. and 5:00 p.m. Assume delivery times follow the continuous uniform dist

german

Answer:

25% of deliveries

Step-by-step explanation:

This is a uniform distribution with parameters a = 1.00 and b =5.00. With these conditions, the following probability distribution functions can be applied:

$P(X \leq x)=\frac{x-a}{b-a}=\frac{x-1.00}{5.00-1.00}\\P(X \leq x) = \frac{x-1}{4}\\P(X \geq x) = 1- P(X \leq x) \\P(X \geq x)=1- \frac{x-1}{4}$

Therefore, the probability that X ≥ 4:00 p.m. is given by

$P(X \geq 4)=1- \frac{4-1}{4}\\P(X \geq 4)=0.25=25\%$

Thus, 25% of deliveries are made after 4:00 p/m.

7 0

3 years ago

Find the mistake made in the steps to solve the equation below.

IgorC [24]

Answer:

B. Step 3 is incorrect, it should be x = 10/8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If you shift the quadratic parent function, f(x)=x2 , right 10 units, what is the equation of the new function?

tiny-mole [99]

Answer:

Step-by-step explanation:

The standard form of a quadratic is

$y=a(x-h)^2+k$ where h is side to side movement (it's also the x coordinate of the vertex) and k is the up or down movement (it's also the y coordinate of the vertex). If there is no up or down movement, the k value is 0. (We don't need to worry about the value for a here; it's 1 but that doesn't change anything for us in our problem). Movement to the right is positive, so we are moving +10. Filling that into our equation: