Answer:
210.0
Step-by-step explanation:
you are rounding to the tens place so you look at the number before it is greater than 5 so you round up getting your answer of 210.0
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
Converse: if 5=x then x+2=7
Inverse: if x+2 doesnt = 7 then x isnt 5
Contrapositive: if x doesnt equal five then x plus two doesnt equal seven
Step-by-step explanation:
We just did this last week :)
Answer:
i would pick line c and e before i would do a and e and b fnhwbh bfrhb bdh hejwhjd febhrew
Step-by-step explanation:
