3x^2+11x-4=10x-1
3x^2+11x-10x-4+1=0
3x^2+x-3=0
Δ=1^1-4*3*(-3)=1+36=37
x1=(-1+V37)/6
x2=( -1-V37)/6
The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
Let x = length of base and leg
The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base
P = b₁ + b₂ + 2(leg)
28 = 3x + 5x + 2(x)
28 = 8x + 2x
28/10 = 10x/10
2.8 = x
Now, substitute the values:
P = b₁ + b₂ + 2(leg)
28 = 3(2.8) + 5(2.8) + 2(2.8)
28 = 8.4 + 14 + 5.6
28 = 28
Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
Answer:
(2k+1)(k+3)
Step-by-step explanation:
14k²+49k+21
simplify by dividing the whole equation by 7
2k²+7k+3
factorise
(2k+1)(k+3)
To represent the solution set of a linear equation parametrically, we introduce other parameters like s and t for the free variables.
Every linear equation has n - 1 free variables where n is the number of variables.
For x + y + z = 2, we have 3 variables and 3 - 1 = 2 free variables.
First, let y and z be the free variables, we first solve the linear equation for x to get:
x = 2 - y - z
Therefore , the parametric representation of the solution set is given by :
x = 2 - s -t
y = s
z = t
Learn more about The linear Equation at:
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Answer:
yus
Step-by-step explanation:
