The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.
95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
Answer:
18.84 in
Step-by-step explanation:
C= 2(pi)r
c= 2(3.14)(3)
c=18.84 in
Im not 100% sure but I believe it is 4/14 chance or 3.5
Your main choices here are (1) a calculator with statistical functions and (2) a table of z-scores.
(a) On my TI-83 Plus calculator I typed in normcdf(-1000, 0.92). The calculator returned the value 0.821. This is approx. 8/10 of the total area under the std normal curve.
(b) I typed in normcdf(-1000, -1.26) and got 0.104
(c) I typed in normcdf(-1000, -0.64) and got 0.261
(d) I typed in normcdf(-1000, -1.09) and got 0.138
Answer:
the probability if that is what you are asking for is 1/3 of winning a prize
Step-by-step explanation: