Ejercicio 3: mi casa tiene medidas 5m de ancho por 15 de largo. Se quieren cubrir 72 m2 con baldosas

Mathematics

2 answers:

In-s [12.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

Mandarinka [93]3 years ago

3 0

A:))))))))))))))))))))))))

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Help? Please. I really need help

tia_tia [17]

Answer:

Step-by-step explanation:

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3 years ago

Write the following equation in logarithmic form <br> a^(4b-6)=3c+d

Tomtit [17]

Hello from MrBillDoesMath!

Answer: (4b-6) log(a) = log (3c + d)

Discussion:

Take the log of both sides of the equation:

log ( a ^(4b-6)) = log (3c + d)

As the log functions causes exponents to become multiplexers, this equation is the same as

(4b-6) log(a) = log (3c + d)

Thank you,

MrB

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Read 2 more answers

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$