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2 years ago

For each value of u, determine whether it is a solution to 2+9u<-16.

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

8 0

Answer:

7: no ( the answer will be 65 )

-2 : no ( the answer will be -16 and -16 is not less than -16 instead they're equal)

2 : no ( the answer will be 20 )

-7 : no ( the answer will be -61)

Non of them satisfy the condition

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10-d = -34-5d solve this equation

algol13

<h3><u>Explanation</u></h3>

Given the equation.

$10 - d = - 34 - 5d$

Solve the equation for d-term.

Because we cannot subtract or add up constants and variables, we simply move the same variable term to the same side and constant term to the same constant side.

$10 + 34 = - 5d + d \\ 44 = - 4d \\ \frac{44}{ - 4} = d \\ - 11 = d$

Answer Check

Substitute d = -11 in the equation.

$10 - ( - 11) = - 34 - 5( - 11) \\ 10 + 11 = - 34 + 55 \\ 21 = 21$

The equation is true for d = -11.

<h3><u>Answer</u></h3>

<u> $\large \boxed{d = - 11}$ </u>

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2 years ago

Read 2 more answers

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

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3 years ago

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madreJ [45]

Answer:

23 inches

Step-by-step explanation:

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