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Pani-rosa [81]
3 years ago
14

For each value of u, determine whether it is a solution to 2+9u<-16.

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

7: no ( the answer will be 65 )

-2 : no ( the answer will be -16 and -16 is not less than -16 instead they're equal)

2 : no ( the answer will be 20 )

-7 : no ( the answer will be -61)

Non of them satisfy the condition

Hope this helped

Hope this helped ALL THE BEST!!

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Write the polar coordinates (3, π) in rectangular form.
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Factor out the greatest common factor. <br><br> x^3-3x^2-x
Andrews [41]

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Factor out the greatest common factor.

x^3-3x^2-x

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Find the values of x and y. Write your answers in simplest form
SCORPION-xisa [38]

Answer:

x =6

y=6\cdot \sqrt{2}

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios. There are six trigonometric ratios: sine, cosine, tangent, cosecant, secant, and cotangent.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Choosing any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image shows a right triangle where the angle of 45° has x as the opposite leg, 6 as the adjacent leg, and y as the hypotenuse. The trigonometric ratio that applies here is the cosine ratio, defined as:

\displaystyle \cos\theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 45^\circ=\frac{6}{y}

Solving for y:

\displaystyle y=\frac{6}{\cos 45^\circ}

\cos 45^\circ=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}

Substituting:

\displaystyle y=\frac{6}{\frac{1}{\sqrt{2}}}

y=6\cdot \sqrt{2}

Now use the tangent ratio:

\displaystyle \tan\theta=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 45^\circ=\frac{x}{6}

Solving for x:

x=6\cdot\tan 45^\circ

\tan 45^\circ=1

Substituting:

x=6\cdot 1

x =6

Answer:

x =6

y=6\cdot \sqrt{2}

6 0
3 years ago
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