Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers
.
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,
Divide both sides by 11.
So, the smaller even integer is -28.
So, the larger even integer is -26.
Answer:
C) 14
Step-by-step explanation:
Option C is the correct answer.
Answer:
idk bc it doesnt show
Step-by-step explanation:
put the answer in!!
Answer:
B: (x + 2)(x - 3)^2
Step-by-step explanation:
This is only going to have 3 roots. One of them is (x - 3)
D does not look right. So let's solve it using synthetic division.
3 || 1 - 4 -3 18
3 -3 -18
========================
1 -1 -6 0
So what you have is a quadratic
- x^2 - x - 6 = 0 which will factor
- (x - 3)(x + 2) = 0
- x - 3 = 0
- x = 3
- x + 2 =0
- x = - 2
- (x - 3)(x - 3)(x + 2 ) = 0
The answer is B
