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kari74 [83]
3 years ago
7

Which expression shows the result of applying the distributive property to  12(5y+4) ?

Mathematics
2 answers:
yan [13]3 years ago
8 0
The answer would be 60y+48
Ber [7]3 years ago
4 0

Just took the quiz (:

The answer is d) 60y + 48

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What is the equation of the quadratic function that has a minimum at (7.-3) and goes through (9.9)?
bixtya [17]

Answer:

X² - 14x + 48= 0

Step-by-step explanation:

To find the quadratic equation well have to look for the root of the equation.

So the roots are at x= 6 and x= 8

The quadratic curve didn't pass the origin .

It intercepted the x axis at 6 and 8 and that's the roots.

So our equation is

(X-6)(x-8)= x²-8x -6x +48

X² - 14x + 48= 0

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3 years ago
The table shows the number of balls, by sport, in the gym. Select the true statements about the information in the table.
icang [17]

Answer:

Soccer you use the lease amount of balls and in tennis you use the most

3 0
3 years ago
If Susie has 2 apples and she gave bill 1 how many apples does susie have?
Ludmilka [50]

Answer:

susie has 1 apple

7 0
3 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x4 ln(x) (a) Find the interval on which f is incre
Ainat [17]

Answer: (a) Interval where f is increasing: (0.78,+∞);

Interval where f is decreasing: (0,0.78);

(b) Local minimum: (0.78, - 0.09)

(c) Inflection point: (0.56,-0.06)

Interval concave up: (0.56,+∞)

Interval concave down: (0,0.56)

Step-by-step explanation:

(a) To determine the interval where function f is increasing or decreasing, first derive the function:

f'(x) = \frac{d}{dx}[x^{4}ln(x)]

Using the product rule of derivative, which is: [u(x).v(x)]' = u'(x)v(x) + u(x).v'(x),

you have:

f'(x) = 4x^{3}ln(x) + x_{4}.\frac{1}{x}

f'(x) = 4x^{3}ln(x) + x^{3}

f'(x) = x^{3}[4ln(x) + 1]

Now, find the critical points: f'(x) = 0

x^{3}[4ln(x) + 1] = 0

x^{3} = 0

x = 0

and

4ln(x) + 1 = 0

ln(x) = \frac{-1}{4}

x = e^{\frac{-1}{4} }

x = 0.78

To determine the interval where f(x) is positive (increasing) or negative (decreasing), evaluate the function at each interval:

interval                 x-value                      f'(x)                       result

0<x<0.78                 0.5                 f'(0.5) = -0.22            decreasing

x>0.78                       1                         f'(1) = 1                  increasing

With the table, it can be concluded that in the interval (0,0.78) the function is decreasing while in the interval (0.78, +∞), f is increasing.

Note: As it is a natural logarithm function, there are no negative x-values.

(b) A extremum point (maximum or minimum) is found where f is defined and f' changes signs. In this case:

  • Between 0 and 0.78, the function decreases and at point and it is defined at point 0.78;
  • After 0.78, it increase (has a change of sign) and f is also defined;

Then, x=0.78 is a point of minimum and its y-value is:

f(x) = x^{4}ln(x)

f(0.78) = 0.78^{4}ln(0.78)

f(0.78) = - 0.092

The point of <u>minimum</u> is (0.78, - 0.092)

(c) To determine the inflection point (IP), calculate the second derivative of the function and solve for x:

f"(x) = \frac{d^{2}}{dx^{2}} [x^{3}[4ln(x) + 1]]

f"(x) = 3x^{2}[4ln(x) + 1] + 4x^{2}

f"(x) = x^{2}[12ln(x) + 7]

x^{2}[12ln(x) + 7] = 0

x^{2} = 0\\x = 0

and

12ln(x) + 7 = 0\\ln(x) = \frac{-7}{12} \\x = e^{\frac{-7}{12} }\\x = 0.56

Substituing x in the function:

f(x) = x^{4}ln(x)

f(0.56) = 0.56^{4} ln(0.56)

f(0.56) = - 0.06

The <u>inflection point</u> will be: (0.56, - 0.06)

In a function, the concave is down when f"(x) < 0 and up when f"(x) > 0, adn knowing that the critical points for that derivative are 0 and 0.56:

f"(x) =  x^{2}[12ln(x) + 7]

f"(0.1) = 0.1^{2}[12ln(0.1)+7]

f"(0.1) = - 0.21, i.e. <u>Concave</u> is <u>DOWN.</u>

f"(0.7) = 0.7^{2}[12ln(0.7)+7]

f"(0.7) = + 1.33, i.e. <u>Concave</u> is <u>UP.</u>

4 0
3 years ago
Trina uses 8.6 pints of blue paint and white paint to paint her bedroom walls.
max2010maxim [7]
<h3>Trina uses 3.44 or \frac{ 17.2}{5} pints of white paint</h3>

<em><u>Solution:</u></em>

Given that,

Trina uses 8.6 pints of blue paint and white paint to paint her bedroom walls

3/5 of the amount is blue paint, and the rest is white paint

From given,

3/5 of 8.6 pints is blue paint

Remaining = 1 - \frac{3}{5}\\\\Remaining = \frac{2}{5}

Thus, 2/5 of 8.6 pints is white paint

<em><u>How many pints of white paint did she use to paint her bedroom walls? </u></em>

White\ paint = \frac{2}{5} \times 8.6\\\\White\ paint = \frac{17.2}{5}\\\\White\ paint = 3.44

Thus she uses 3.44 or 17.2/5 pints of white paint

5 0
3 years ago
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