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3 years ago

What is the equation of the quadratic function that has a minimum at (7.-3) and goes through (9.9)?

Mathematics

1 answer:

bixtya [17]3 years ago

7 0

Answer:

X² - 14x + 48= 0

Step-by-step explanation:

To find the quadratic equation well have to look for the root of the equation.

So the roots are at x= 6 and x= 8

The quadratic curve didn't pass the origin .

It intercepted the x axis at 6 and 8 and that's the roots.

So our equation is

(X-6)(x-8)= x²-8x -6x +48

X² - 14x + 48= 0

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The perimeter of triangle RXA is 24. If RX = 4 and RA = 11, find XP and PA

Tju [1.3M]

8 is the answer because when you add 11+4 you get 16 and then you would subtract that from 24 which would give you 8. Idk where you got "PA" ?

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3 years ago

W trójkącie ABC połączono wierzchołek C z punktem D który jest środkiem boku AB . Wyznaczono równierz środek odcinka CD punkt E

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3 years ago

Solve the system of equations. Write you answer as an ordered pair.

lawyer [7]

Answer:

x = -4 y = -5

Step-by-step explanation:

2x + 3 = -x - 9

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3 years ago

What is the value of the expression 2x²- 3x + 7 when x = 3? *

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.......................

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3 years ago

Read 2 more answers

The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

7 0

3 years ago