Write down the possible values for n: -15

two vertical cliffs are on opposite sides of a 90 foot wide river. From point A at the top of the shorter cliff, the angle of el

Sedbober [7]

Answer: The tall cliff is 118.20 feet tall and the short cliff is 70.32 feet tall.

If you draw a picture with 2 cliffs and a river in the middle, you have find 2 right triangles. In each triangle the adjacent side to our known angle is the river of 90 feet. And the unknown side is the opposite leg.

Therefore, we can set up a tangent equation.

From the top of the short cliff to the top of the tall cliff, we can right and solve the following trig equation:

tan(28) = x /90
x = 47.88

From the top of the short cliff to the bottom, we can right and solve the following trip equation.

tan(38) = x/90
x = 70.32

The 70.32 is also the height of the short cliff. And adding the two answers together will give you the height of the tall cliff.

5 0

4 years ago

Which pair shows equivalent expressions?

viva [34]

Answer:

b.

Step-by-step explanation:I think

3 0

3 years ago

Can anyone math experts help and guide me through these questions❓

Lubov Fominskaja [6]

Step-by-step explanation:

The volume of a cube is

$a {}^{3}$

where a is the side length,

Note: If you want to remember this formula, know that a cube is basically a bunch of squares stacked on one another vertically and horizontally

The area of a square with side length a, is

${a}^{2}$

If we multiply that by the height of the cube, which is a.

${a}^{2} \times a = {a}^{3}$

That is the easy way to derive the formula of the volume of a cube.

Back on track, we know the volume so we must solve for a.

1.

$125 = {a}^{3}$

Assuming you took algebra, to isolate the variable a, we must undo it being raised to the third power.

To do this, we take the cube root of both sides

$\sqrt[3]{125} = \sqrt[3]{a {}^{3} }$

The cube root of 125 is 5 so

$5 = a$

5 cm

2.

$8 = {a}^{3}$

$\sqrt[3]{8} = \sqrt[3]{ {a}^{3} }$

$2 = a$

2 ft

3.

$343 = {a}^{3}$

$a = 7$

7 yd

4.

$1000 = a {}^{3}$

$10 = a$

10 mm

5.

$1728 = {a}^{3}$

$a = 12$

12 in. or 1 ft

6.

$1 = {a}^{3}$

$a = 1$

1 m

4 0

2 years ago

Read 2 more answers

The cruise boat can carry up to 45 passengers. The company wants to know the minimum number of passengers needed per cruise to c

denpristay [2]

Fixed price costs
Crew salaries 350
fuel 120
overheads 170
Total fixed cost: 640

Variable costs per passenger
refreshments $ 6.50
refund $ 3.64
total variable cost: 10.14

Sales income
Average ticket $ 36 .40

Break-even point = (fixed costs) 
(income per passenger – costs per passenger) 


Break even = 640 / (36.40-10.14) = 640 / 26.26 = 24.37

3 0

4 years ago

What is the estimate of 1/7 x 20 and 1/9 of 82?

devlian [24]

I believe the answer to 1/7 times 20 would be 2.9 that is rounded to the nearest tenth but if your rounding to the nearest whole number it would be 3
As for 1/9 of 82 it would be 9.1 rounded to the nearest tenth and it would be 9 rounded to the nearest whole number.

3 0

3 years ago

Write down the possible values for n: -15 < 3n ≤ 6