Use the law of cosines.
a2+b2−2abcosC=c2
Find the measure of angle C. It is the opposite side of c.
c2−a2−b2−2ab=cosC
cosC=13.62−22.52−182−2(22.5)(18)≈0.797
C=cos−10.797=0.649 rad=37.19∘
angle B:
a2+c2−2accosB=b2
cosB=b2−a2−c2−2ac
B=cos−1b2−a2−c2−2ac=cos−1182−22.52−13.62−2(22.5)(13.6)≈0.927 rad=53.13∘
angle A:
b2+c2−2bccosA=a2
A=89.68∘
? Is there an equation that comes with this problem?
2x+8y in factor form is 2(x+4y)
Answer:
70
Step-by-step explanation:
I already took the test
