The answer will be A. 471/11. Hope it help!
Answer: 24
A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.
the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.
The general equation for the vertical hyperbola is
[ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1
The conjugate axis of the vertical hyperbola is y = k
Length of the conjugate axis = 2b
According to the question k = 2, h = -1, a = 4, b = 12
Length of the conjugate axis = 2b = 2 * 12 = 24
Learn more about hyperbola here :
brainly.com/question/3351710
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Answer:
X= -0.1290 (bar line on top of the 90)
Hope this helps!
Step-by-step explanation:
Answer: Carlos is correct
Step-by-step explanation:
2x^5-250x^2
The first step is to factorize out 2x^2
2x^2(x^3-125)
This can be rewritten as
2x^2(x^3-5^3),
Recall, difference if cube (a^3-b^3)
= (a-b)(a^2 +ab + b^2)
from our equation,
a= x
b = 5.
So the difference of cubes will be
2x^2[(x-5) (x^2 + 5x + 5^2)]
=2x^2[(x-5) (x^2 + 5x + 25)]
Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.
Amber is incorrect because 125 is equal to b3, not b.
Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.
Answer:
Step-by-step explanation:
Let the equation of the cosine function is,
y = Acos(Bx)
From the graph attached,
A = Amplitude = 
= 1
B = 
B = 
B = 
B = 4
Therefore, equation of the cosine wave given in the graph will be,
y = 1.Cos(4x)
y = Cos(4x)
